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kirza4 [7]
1 year ago
6

4(5x−3)+5x+5 = 118 solve for x

Mathematics
1 answer:
EleoNora [17]1 year ago
8 0

Answer:

x=1+2/15

Step-by-step explanation:

4(5x-3)=5x+5=118

We move all terms to the left:

4(5x-3)-(5x+5)=0

We multiply parentheses

20x-(5x+5)-12=0

We get rid of parentheses

20x-5x-5-12=0

We add all the numbers together, and all the variables

15x-17=0

We move all terms containing x to the left, all other terms to the right

15x=17

x=17/15

x=1+2/15

   

   

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Joseph Kitavich wants to determine his average phone bill so he is better able to budget his expenses. In October, November, and
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To get the avarage you have to add all the bills and divide by the number of months.

89.87+45.67+34.56= 170.1
170.1 ÷3= 56.70
The answer is $56.70.
4 0
2 years ago
For his coffee shop, Abdul wants to make a mocha-java blend that will sell for $18/kg. The mocha coffee beans sell for $20/kg, a
djverab [1.8K]

30 kg of mocha coffee bean and 20 kg of java coffee bean should be used to make 50 kg of mocha java blend that will sell for $ 18 per kg

<em><u>Solution:</u></em>

Let "x" be the kilogram of mocha coffee beans

Let "y" be the kilogram of java coffee beans

Cost of 1 kg of mocha coffee bean = $ 20

Cost of 1 kg of java coffee bean = $ 15

Kilograms of each kind of coffee bean should he use to make 50 kg of the mocha-java blend

Cost of 1 kg of mocha java blend = $ 18

From given information,

Mocha coffee beans and java coffee beans are mixed to get 50 kg of blend

Therefore,

x + y = 50 ------------ eqn 1

Abdul wants to make a mocha-java blend that will sell for $18/kg

<em><u>Therefore, we frame a equation as:</u></em>

(kilogram of mocha coffee beans) x (Cost of 1 kg of mocha coffee bean) + (kilogram of java coffee beans) x (Cost of 1 kg of java coffee bean) = Cost of 1 kg of mocha java blend x 50 kg

Thus we get,

x \times 20 + y \times 15 = 18 \times 50\\\\20x+15y = 900 ------------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>From eqn 1,</u></em>

x = 50 - y -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

20(50 - y) + 15y = 900

1000 - 20y + 15y = 900

5y = 100

<h3>y = 20</h3>

<em><u>Substitute y = 20 in eqn 3</u></em>

x = 50 - 20

<h3>x = 30</h3>

Thus 30 kg of mocha coffee bean and 20 kg of java coffee bean should be used to make 50 kg of mocha java blend that will sell for $ 18 per kg

3 0
2 years ago
Solve y=4x+8x for x
Semmy [17]

Answer:

x = y/12

Step-by-step explanation:

5 0
2 years ago
A science experiment calls for mixing 3 and two-thirds cups of distilled water with 1 and three-fourths cups of vinegar and Two-
Vikentia [17]

Answer:

D. 6 1/12

Step-by-step explanation:

First add the like fractions.

3 2/3 + 2/3 = 3 4/3 (Don't worry about simplifying yet)

Now find the least common multiple for 3 4/3 and 1 3/4 so we can add them.

<h2>REMEMBER: You can only add and subtract fractions when they have the same denominator.</h2>

3: 3, 6,  9, 12

4: 4, 8, 12

In this case 12 is the least common multiple.

3/4 x 3/3 = 9/12    9/12

4/3 x 4/4 = 16/12

Add those two fractions then add the whole numbers and put it in front.

4 25/12

Simplify

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7 0
1 year ago
Read 2 more answers
A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is
MakcuM [25]

Answer:

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 5 minutes

Sample mean, \bar{x} = 4.61 minutes

Sample size, n = 15

Alpha, α = 0.05  

Sample standard deviation, s = 0.75 minutes

a) First, we design the null and the alternate hypothesis  

H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}  

We use two-tailed t test to perform this hypothesis.  

b) Formula:  

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have  

t_{stat} = \displaystyle\frac{4.61 - 5}{\frac{0.75}{\sqrt{15}} } = -2.0139  

c) Now, we calculate the p-value using the standard table.

P-value = 0.0638

d) Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean amount of time that college students spend in the shower is equal to 5 minutes.

Option a) Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05.

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2 years ago
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