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vivado [14]
2 years ago
10

The probability that a student at your school takes Drivers Education and Spanish is 87/1000. The probability that a student tak

es Spanish is 68/100. What is the probability that a student takes Drivers Ed given that the Student is taking Spanish?
Mathematics
2 answers:
Gnom [1K]2 years ago
5 0
Let
x---------> <span>The probability that a student takes Spanish 
y-------> </span><span>the probability that a student takes Drivers Education given that the Student is taking Spanish
z-------> </span><span>The probability that a student at school takes Drivers Education and Spanish 

we know that
z=x*y------> solve for y
y=z/x
z=87/1000
x=68/100
substitute
y=(87/1000)/(68/100)-----------> y=87/680

the answer is
87/680</span>
TEA [102]2 years ago
5 0

Answer: The probability is P = 0.128

Step-by-step explanation:

The data we have is:

The probability of a student to take drivers education and Spanish is 87/1000.

The probability that a student takes Spanish is 68/100.

Now, remember that if for event 1 we have the probability p1, and for event 2 we have the probability p2, the probability of both events happening is:

P = p1*p2

This is the case for the student that takes the two classes, but when we assume that the student takes Spanish, we can remove the probability of that event (because we are already looking at the 68/100 of the cases where the student selected Spanish)

So given that a student is tanking Spanish, the probability of him to take drivers ed is:

(Probability of both classes)/(probability of tanking Spanish)

P = (87/1000)*(100/68) = 0.128

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15 PINTS!!!!!!!!! PLZ HELP!!!!!!!! The linear function f(x) = 0.5x + 80 represents the average test score in your math class, wh
Stells [14]

Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x,   q(x)

1,     81

2,    83

3,    85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

4 0
1 year ago
According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

This is a left tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

µ = population mean = 17

s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0
2 years ago
Your lab develops a synthetic compound that is extremely light but very durable. You test it by making a solid ball with a radiu
Maksim231197 [3]
The volume of a spherical shaped object is given by

V= \frac{4}{3} \pi r^3

Given that the <span>solid ball has a radius of 20.0 millimeters, the volume of the solid ball is given by

V= \frac{4}{3} \pi(20)^3\approx33,510mm^3

Therefore, the </span><span>closest to the volume of the synthetic compound ball, in cubic millimeters is 33,500 cubic milimeters.</span>
6 0
2 years ago
For which values of a the system has no solution: x≤5, x≥a
soldi70 [24.7K]

Given:

The system of inequalities is

x\leq 5

x\geq a

To find:

The values of a for which the system has no solution.

Solution:

We have,

x\leq 5        ...(1)

It means the value of x is less than or equal to 5.

x\geq a        ...(2)

It means the value of x is greater than or equal to a

Using (1) and (2), we get

a\leq x\leq 5

But if a is great than 5, then there is no value of which satisfies this inequality.

Therefore, the system has no solution for a>5.

7 0
2 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

Sample size = n = 16

We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = t_{\frac{\alpha}{2}} = 2.131

The formula to calculate the confidence interval is:

(x-t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} }, x+t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} })

We have all the required values. Substituting them in the above expression, we get:

(620-2.131 \times \frac{45}{\sqrt{16} }, 620+2.131 \times \frac{45}{\sqrt{16} })\\\\ =(596.0 , 644.0)

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)

7 0
2 years ago
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