one angle of a linear pair is 10 more than two thirds the other angle. find the measure if both angles
1 answer:
Answer:
One Angle = 110°
Other Angle = 70°
Step-by-step explanation:
A linear pair means that two angles are in a straight line (or, a straight angle).
A straight line is 180 degrees.
THey are supplementary.
We can say one angle is "a" and another one is "b".
<em>One angle is 10 MORE THAN 2/3rds of the other, we can write:</em>
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<em>Also, since they are supplementary (add up to 180), we can write:</em>
<em>a + b = 180</em>
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We can now substitute 1st equation in this one and find b:
Since a + b = 180, we can write:
a + 110 = 180
so,
a = 180 - 110
a = 70
Thus,
One Angle = 110°
Other Angle = 70°
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Answer:
100 in²
Step-by-step explanation:
The area of the banner is equal to the area of the initial rectangle minus the area of the cutout triangle.
The rectangle has a height of 8 inches and width of 14 inches, so its area is:
A = (8 in) (14 in) = 112 in²
The triangle has a base of 8 inches and a height of 3 inches, so its area is:
A = ½ (8 in) (3 in) = 12 in²
So the area of the banner is 112 in² − 12 in² = 100 in².
Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
