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1 year ago

11

Malik's arts and crafts shop have a bolt of crimson velvet 32 meters long. A customer came in during the morning and bought 120

centimeters of the velvet. Another customer bought an additional 14 meters during the afternoon. How much crimson velvet does Malik's shop have left? Write the answer in centimeters.

2 answers:

krek1111 [17]1 year ago

4 0

1,680 centimeters of crimson velvet

Eva8 [605]1 year ago

3 0

Answer: 3200-1520=1680 cm

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B or C hope its helps...

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A function f(x) has x intercepts of -3 and -5. What is the constant term in the function?

Anon25 [30]

Answer:

The constant term in the function is 5

Step-by-step explanation:

we have

$f(x)=x^{2}+8x+b$

where

b is the y-intercept or the constant term of the function

Remember that

The x-intercept is the value of x when the value of the function is equal to zero

so

For x=-3 ----> f(x)=0

For x=-5 ----> f(x)=0

substitute any of the intercepts in the function

For x=-3

$0=(-3)^{2}+8(-3)+b$

$0=9-24+b$

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Verify with the other intercept

For x=-5

$0=(-5)^{2}+8(-5)+15$

$0=25-40+15$

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therefore

The constant term in the function is 5

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2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

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We have then:

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Evaluating for x = 3:

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$AVR = \frac{18-(-2)}{3-(-2)}$

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$AVR = \frac{20}{5}$

$AVR = 4$

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$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

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Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

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Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

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1 year ago

On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapid

Anon25 [30]

Answer:

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Step-by-step explanation:

This is going to be an exponential function as it grows rapidly.

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x=t/22

a=7600

r=5

∴y=7600(5^(t/22))

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2 years ago

According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1

JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means $p=0.10$ and $q=1-0.10=0.90$ .

If 1100 Americans are sampled, then the sample size is $n=1100$ .

The mean of the distribution is $\mu=np$ .

This means $\mu=1100\times 0.10=110$

The standard deviation is $\sigma=\sqrt{npq}$

We substitute the values to get:

$\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95$

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We first apply the continuity correction factor to get: $P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)$

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$P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)$

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$P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48$

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We apply the CCF to get:

$P(X\le88)=P(X\:$

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3 0

2 years ago