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Varvara68 [4.7K]
2 years ago
6

Which triangle is similar to ΔJKL? ΔJKM, ΔMKL, ΔKML, ΔLJK.

Mathematics
2 answers:
kirill [66]2 years ago
7 0
The answer would be ΔKML because the right angle of ΔKML is in the same place as <span>ΔJKL</span>
nadezda [96]2 years ago
4 0

Answer:

Triangle \triangle KML is similar to the given triangle \triangle JKL.

Step-by-step explanation:

Let us analyze the given options one by one.

\triangle JKM is not similar to the triangle \triangle JKL because it is not written in correct order. The way we write the triangle (order of vertices) is very important. Since angles K of both the triangles are not equal, therefore, order is messed up. If the order had been \triangle JMK then this would have been correct.

\triangle MKL is not similar to triangle \triangle JKL because the corresponding angles are not equal. Again the order it not right. If the order had been \triangle KML, then this option would have been correct.

\triangle KML is similar to the given triangle \triangle JKL because corresponding angles of both the triangles are equal.

\triangle LJK is not similar to the given triangle \triangle JKL because the corresponding angles of the two triangles are not equal.

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The length of side st is 15.

Step-by-step explanation:

A tangent is a straigth line that touches a circle externally at a point on the circumference. Considering one of its properties that tangents from the same point to a fixed point outside a circle are equal.

Then,

     /rn/ = /rp/

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But, /rp/ = 7, /rt/ = 17 and /sm/ = 5.

Then,

 /rt/ = /rn/ + /tn/

17 = 7 + /tn/ (∵ /rp/ = /rn/ = 7)

⇒ /tn/ = 10

Since /nt/ = 10, then /tm/ = 10 (/tm/ = /nt/)

So that,

 /st/ = /sm/ + /tm/

     = 5 +10

 /st/ = 15

The length of side st is 15.

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