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Radda [10]
2 years ago
5

Phil has 3 times as many rocks as Peter. Together, they have 48 rocks. How many more rocks does Phil have than Peter?

Mathematics
2 answers:
shtirl [24]2 years ago
7 0
Peter= x
Phil=3x
Implies that 4x=48 which means x=12
Implies that Phil has 36 rocks
36-12=
24 more rocks
Ivan2 years ago
3 0
Let x = the number of marbles for Phil
Then 3x = the number of marbles for Peter
Together they have 3x+x=48 or 4x=48 and x=12
So Phil has x = 12 marbles and Peter has 3x, let x = 12, 3(12) = 36 marbles.
Peter has 24 more marbles than Phil.
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Given: mKP=2mIP, mIVK =120°<br> Find: m∠KJL.
anzhelika [568]

Answer:

<h2>The measure of angle KJL is 40°.</h2>

Step-by-step explanation:

Givens

m(KP)=2m(IP)

m(IVK)=120\°

Notice that

m(KP)+m(IP)+m(IVK)=360\°, by definition sum of arcs.

Replacing given values, we have

2m(IP)+m(IP)+120\°=360\°\\3m(IP)=360\° - 120\°\\m(IP)=\frac{240\°}{3}\\ m(IP)=80\°

Which means m(KP)=2(80\°)=160\°

Notice that arc KP is the subtended arc by angle KJL.

We know that the angle formed by a tangen and a secant is equal to one-half of the difference of the intercepted arcs.

m\angle KJL = \frac{1}{2} (m(KP)-m(IP))\\m \angle KJL = \frac{1}{2}(160\° - 80\° )=\frac{1}{2}(80\°)=40\°

Therefore, the measure of angle KJL is 40°.

8 0
2 years ago
Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t
Helga [31]

Answer:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

Minimum = 9 represent the minimum value

Q_1 = 18 represent the first quartile

Median =Q_2= 21 represent the median

Q_3 = 28 represent the third quartil

Maximum=56 represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0
2 years ago
Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y
lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

  1. Translate one of the two circles so that they have the same center
  2. Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well

Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

  1. Start with circle X and radius r
  2. Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
  3. Scale the radius of circle X' until it becomes s. This new circle, say X'', is similar to X' because you only scaled it

So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

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Mazyrski [523]

Answer:

6^2

Step-by-step explanation:

The square root of a perfect square is a rational number.

So let us take the square root of each number to see which is a rational number.

\sqrt{6^1}=\sqrt{6}......irrational

\sqrt{6^2}=6......rational

\sqrt{6^3}=6\sqrt{6}.........irrational

\sqrt{6^5}=36 \sqrt{6}irrational.

Therefore 6^2 is a perfect square

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2 years ago
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Alex is 1.6 m tall and Noah is 1.5 times as tall as Alex. How much taller is Noah in centimeters?​
nika2105 [10]

Answer:

80 centimeters taller

Step-by-step explanation:

First, convert Alex's height from meters to centimeters by multiplying by 100 because there are 100 centimeters in one meter to get 160 centimeters. Now multiply 160 centimeters by 1.5 to get Noah's height, 240 centimeters. Finally, since we need to find their difference in height, subtract Alex's height of 160 centimeters from Noah's height of 240 to get 80 centimeters.

8 0
2 years ago
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