Answer:
There is no evidence that there is no significant difference between the sample means
Step-by-step explanation:
given that a statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points
The two-tailed students average 7.64 points, and their standard deviation is 1.33 points.
Group One tailed X Two tailed Y
Mean 7.8100 7.6400
SD 1.0600 1.3300
SEM 0.1185 0.1487
N 80 80

(Two tailed test)
The mean of One tailed X minus Two tailed Y equals 0.1700
t = 0.8940
df = 158
p value =0.3727
p is greater than alpha 0.05
There is no evidence that there is no significant difference between the sample means
0.813 is your answer because 7 is higher than 5 which means you have to round it up and not down
To answer problems like this you have to use binomial:
P (x > 1) = 1 – p (0
< x < 1) > .7
So:
1 – p (0) – p (1) >
.7
1 – (3/ 4) ^n – (3/ 4)
^n (n – 1 ) (1/ 4) > .7
Therefore n > 5.185,
and the smallest value of n so that we can satisfy the given condition is 6
(rounded up)
<span> </span>
Part A: f(x)=(5)x+20(alligators) and f(x)=(10)x+25(crocodiles)
Part B: f(x)=(5)(4)+20(alligators) and f(x)=(10)(4)+25(crocodiles)
Alligators: 40 and Crocodiles: 65
Part C: None because the rate of the alligators won't catch up with the rate of crocodiles.