Answer:
Scalene triangle
Step-by-step explanation:
scalene triangle is a triangle where the lengths of all three sides are different, it comprises of both obtuse and acute angles,all giving a sum of 180 degrees
The domain is the x values
y = 2 - x
when x = -3
y = 2 - (-3)
y = 2 + 3
y = 5....so ur points are (-3,5)
when x = -2
y = 2 - (-2)
y = 2 + 2
y = 4....so ur points are (-2,4)
when x = -1
y = 2 - (-1)
y = 2 + 1
y = 3...so ur points are (-1,3)
when x = 0
y = 2 - 0
y = 2....so ur points are (0,2)
when x = 1
y = 2 - 1
y = 1...so ur point are (1,1)
so basically, u plot all of those points
Answer:
36 erasers
Step-by-step explanation:
Let number of erasers be e
let number of rulers be r
We can write:
e + r = 70
and
After giving away, he has
Erasers: 2/3e
Rulers: r - 10
These two are equal, so we can write and solve:
2/3e = r - 10
2/3e + 10 = r
Putting this in initial equation, we have:
e + (2/3e + 10) = 70
5/3e + 10 = 70
5/3 e = 60
e = 36
And rulers is:
r = 2/3(36) + 10 = 34
Hence, he had 36 erasers in the beginning
Answer:
28 feet
Step-by-step explanation:
area of a square = side times side; the sides are equal
50 = side times side or 50 = side^2
sqroot of 50 = sqroot of side^2
7 feet is about the size of the side of the square so using that information..
2 length + 2 width or 4 side
4 times 7 = 28
the perimeter is 28 feet
Answer:
a) ![[-0.134,0.034]](https://tex.z-dn.net/?f=%5B-0.134%2C0.034%5D)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where
.
The mean difference
.
The confidence interval is

![= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]](https://tex.z-dn.net/?f=%3D%20-0.05%5Cpm%201.995%20%5Ctimes%200.042%20%3D%20-0.05%20%5Cpm%200.084%20%3D%20%5B-0.134%2C0.034%5D)
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.