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dem82 [27]
2 years ago
14

Korey’s comic book store has been up and running for 4 years. Korey feels that his store has been successful and is considering

moving to a larger property to allow for greater inventory and customer opportunities in his business. He would like investors to cover the cost of his expansion.
The profits of Korey’s comic book store for its first four years are outlined below. According to this information, what would be the best estimate for Korey to quote as expected profits in the next year in his new business plan?
Year
Net Profits
1
$14,250.00
2
$15,390.00
3
$16,621.20
4
$17,950.90
5


a.
$20,550.19
b.
$19,090.90
c.
$19,280.60
d.
$19,386.97
Mathematics
2 answers:
Inessa05 [86]2 years ago
8 0
Year      Net Profit
1            <span>$14,250.00
2            $15,390.00
3            $16,621.20
4            $17,950.90</span>2

We need to get the increase of the net profit of the current year from the previous year.

Percentage increase = (Current year - Previous Year)/ Previous Year    * 100%

Year 2:  (15,390 - 14, 250) / 14,250   * 100% = 0.08 * 100% = 8%
Year 3: (16,621.20 - 15,390) / 15,390 * 100% = 0.08 * 100% = 8%
Year 4: (17,950.90 - 16,621.20) / 16,621.20 * 100% = 0.08 * 100% = 8%

Every year the net income increases by 8%. So, the net income in Year 5 will be:

17,950.90 x 1.08 = 19,386.97  Choice D.

ira [324]2 years ago
6 0
D. $19,386.97 is the right answer
had it on a test
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1 year ago
Complete the equation of the line through (-6,5)(−6,5)left parenthesis, minus, 6, comma, 5, right parenthesis and (-3,-3)(−3,−3)
goldenfox [79]

Answer:

The answer to your question is:   y = -8/3 x - 11

Step-by-step explanation:

A (-6, 5)

B (-3, -3)

Process

1.- Find the slope of the line

Formula

             m = \frac{y2 - y1}{x2 - x1}

Substitution

             m = \frac{-3 - 5}{-3 + 6}

Simplifying

            m = \frac{- 8 }{3}

2.- Find the equation of the line

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Substitution

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Simplifying

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4 0
1 year ago
A karate center has 120 students. The director wants to set a goal to motivate her instructors to increase student enrollment. U
iVinArrow [24]
A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.

B) To solve this problem we will use formula for a growth of population:
final = initial * (1+percentage)^{t}
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years

We can insert numbers and solve for t:
240= 120* (1+0.12)^{t}  \\ 2=1.12^{t}   \\ log2=log(1.12^{t} ) \\ log2=t*log1.12 \\ t= \frac{log2}{log1.12}  \\ t=6.12years

For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years

Plan B is better to double the <span>enrollment.


C)We use same steps as in B) to solve this.
</span>

360= 120* (1+0.12)^{t} \\ 3=1.12^{t} \\ log3=log(1.12^{t} ) \\ log3=t*log1.12 \\ t= \frac{log3}{log1.12} \\ t=9.69years

For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years

Plan A is better to triple the enrollment.
3 0
2 years ago
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