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2 years ago

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A sample of 2,845 auto workers was selected to learn if they would go on strike. Over 50% of those in the sample declared they w

ould strike. We can assume that the majority of all auto workers favor a strike since the number sampled is large and those in favor of a strike are over 50%. True False

1 answer:

bogdanovich [222]2 years ago

5 0

Answer:

This condition is true.

Step-by-step explanation:

A sample of 2,845 auto workers was selected to learn if they would go on strike.

Over 50% of those in the sample declared they would strike.

We can assume that the majority of all auto workers favor a strike. This is true because, in the sample, it is declared that 50% of workers would strike.

And this sample represents the whole majority or population. Hence we can say that a majority of all auto workers favor a strike.

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You buy a pair of jeans at a department store. Jeans 39.99 Discount -10.00 Subtotal 29.99 Sales tax 1.95 Total 31.94 a. What is

Mariana [72]

A)

if 39.99 is the 100%, what is 10 in percentage? well

$\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
39.99&100\\
10&x
\end{array}\implies \cfrac{39.99}{10}=\cfrac{100}{x}$

solve for "x".

b)

now, with the discount, the amount is 29.99, thus if 29.99 is the 100%, what is 1.95 from it in percentage?

$\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
29.99&100\\
1.95&x
\end{array}\implies \cfrac{29.99}{1.95}=\cfrac{100}{x}$

solve for "x".

c)

the original price is 39.99, the markup on that is 60%, how much is that?
well

$\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
39.99&100\\
x&60
\end{array}\implies \cfrac{39.99}{x}=\cfrac{100}{60}\implies 39.99\cdot 60=100x
\\\\\\
\cfrac{39.99\cdot 60}{100}=x\implies 23.994=x$

now, after the discount, the price is 29.99, how much is 23.994 in percentage of 29.99?

well $\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
29.99&100\\
23.994&x
\end{array}\implies \cfrac{29.99}{23.994}=\cfrac{100}{x}$

solve for "x".

8 0

2 years ago

If you are a student with no assets of any value and have liability insurance on an old car that pays a maximum of $50,000 per a

svetoff [14.1K]

Answer:

D

Step-by-step explanation:

they will sue for the rest of the money, because they are entitled to it if you are the cause of an accident.

6 0

2 years ago

A cake has a mass of 2.5kg. It contains 275g of fruit. What percentage of fruit is there in the cake

Travka [436]

The answer is: "11 %" .
__________________________________
There is 11% of fruit in the cake.
______________________________
Explanation:
____________________________________

275g is what percent of 2.5 kg?

First, convert "275 g" into "kg".

Note the exact conversion: 1000 g = 1 kg .

So 275 g = (275/1000) kg = 0.275 kg .

0.275 kg = (n/100) * 2.5 kg ;

→ (n/100) * 2.5 = 0.275 ;
____________________________
Divide each side by "(2.5)"
______________________
→ (n/100) = (0.275) / (2.5) ;

→ (n/100) = 0.11 ;

Multiply each side by "100" ;

n = 11 .
________________________________________
The answer is: 11 % .
________________________________________

8 0

2 years ago

Read 2 more answers

Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble

Jlenok [28]

33 in because 1056 divided by 32 is 33
hope you pass your test

3 0

1 year ago

Read 2 more answers

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

<u>Given:</u>

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

1 year ago

Read 2 more answers