Answer:
a) 0.00019923%
b) 47.28%
Step-by-step explanation:
a) To find the probability of all sockets in the sample being defective, we can do the following:
The first socket will be in a group where 5 of the 38 sockets are defective, so the probability is 5/38
The second socket will be in a group where 4 of the 37 sockets are defective, as the first one picked is already defective, so the probability is 4/37
Expanding this, we have that the probability of having all 5 sockets defective is: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%
b) Following the same logic of (a), the first socket have a chance of 33/38 of not being defective, as we will pick it from a group where 33 of the 38 sockets are not defective. The second socket will have a chance of 32/37, and so on.
The probability will be (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%
A=16500(1-0.0575)^5
A=16,500×(1−0.0575)^(5)
A=12,271.30
Answer:
It c
Step-by-step explanation:
I have done this before! Have a nice day!
Answer:
a = 20 . . . . liters
Step-by-step explanation:
To solve this, multiply the equation by 30+a:
a = 0.4(30 +a)
a = 12 + 0.4a . . . . . eliminate parentheses
0.6a = 12 . . . . . . . . subtract 0.4a
a = 12/0.6 = 20 . . . divide by the coefficient of a
20 L of alfalfa must be added
_____
<em>Check</em>
20/(30+20) = 20/50 = 40/100 = 0.4 . . . . . . answer checks OK
