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2 years ago

PLEASE ANSWER FOR BRIANLIEST(08.06)

1 answer:

4 0

Hey

solve. w+11=3w-15 2w=26 w=13 b=w+11 b=(13)+11= 24
So the answer is <span>Solve w + 11 = 3w − 15 to find the value of w = 24
</span>
Hoped I Helped

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PLEASE HELP!!!!!!!!! Ernest's friend rolls a six-sided number cube and lands on square 8. She asks Ernest to guess what number s

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Answer:

he reads

Step-by-step explanation:

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1 year ago

A pie was a radius of 4.25 inches

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Do you want to find the area for this or circumference. If you want to find the area, the answer will be about 56.7 square inches. Finally, if you want to find the circumference, the answer will be about 26.69 inches. Hope you get it!

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2 years ago

Product A is an 8oz. Bottle of cough medicine that sells for $1.36. Product B is a 16oz. Bottle cough medicine that costs $3.20.

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Product A= 8oz = 1.36 x 2= 2.72. 16oz = 2.72

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2 years ago

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A set of data points has a line of best fit of y=2.5x-1.5

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To solve this problem you must apply the proccedure shown below:

1- You must apply the following formula:

$R=yo-yp$

Where $R$ is the residual, $yo$ is the observed value $y$ and $yp$ is the predicted value $y$ .

2- You only need to substitute the $x=5$ into the equation $y=2.5x-1.5$ and then, you must apply the formula for calculate the residual:

$y=2.5(5)-1.5\\ y=11$

$R=12-11\\ R=1$

The answer is: The residual is $1$

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2 years ago

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir

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Answer:

a) $\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

b) $Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

c) $\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

If we apply this formula for the four methods we got:

$\bar X_A =22.744$

$\bar X_B =20.7$

$\bar X_C =21.013$

$\bar X_D =18.306$

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

$Median_A =\frac{23+24}{2}=23.5$

$Median_B =\frac{20.4+20.4}{2}=20.4$

$Median_C =\frac{21+21}{2}=21$

$Median_D =\frac{20.7+20.7}{2}=20.7$

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

$\bar X_A =23.25$

$\bar X_B =20.7$

$\bar X_C =21.04$

$\bar X_D =20.69$

3 0

1 year ago

*PLEASE ANSWER FOR BRIANLIEST*(08.06)

PLEASE ANSWER FOR BRIANLIEST(08.06)