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Andre45 [30]
2 years ago
7

A 2-column table with 10 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1,

2, 3, 4, 5. The second column is labeled f of x with entries 105, 0, negative 15, 0, 9, 0, negative 15, 0, 105, 384. According to the table, which ordered pair is a local minimum of the function, f(x)?
Mathematics
2 answers:
dangina [55]2 years ago
7 0

Answer:

A, D, and E on edgenuity

Step-by-step explanation:

Murrr4er [49]2 years ago
5 0

Answer-  A,D,E

Step-by-step explanation:

A two column table with 5 rows. The first column, x, has the entries, negative 2, 0, 2, 4. The second column, y, has the entries, 6, 3.5, 1, negative 1.5.

Which equations represent the data in the table? Check all that apply.

y – 6 = y minus 6 equals StartFraction negative 5 Over 4 EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)

y – 2 = –y minus 2 equals negative StartFraction 5 Over 4 EndFraction left-parenthesis x minus 1 right-parenthesis.(x – 1)

y + 2 = y plus 2 equals StartFraction negative 5 Over 4 EndFraction left-parenthesis x minus 6 right-parenthesis.(x – 6)

y – 1 = –y minus 1 equals negative StartFraction 5 Over 4 EndFraction left-parenthesis x minus 2 right-parenthesis.(x – 2)

y – 3.5 = –1.25x

Im just rephrasing the question

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Step-by-step answer:

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Answer:

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Alternative hypothesis:p > 0.113  

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Replacing we got:

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Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the  workers belonged to unions

\hat p=\frac{52}{400}=0.13 estimated proportion of workers belonged to unions

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\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

Part b

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z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

Part c

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