Step-by-step answer:
Area of a kite is half of the product of the diagonals.
The length of diagonal in the x-direction is 4+5 = 9
The length of diagonal in the y-direction is 4+4 = 8
Therefore
Area of kite = 8*9/2 = 36 units.
Answer:
0.1/4-3/20=1/40-6/40=-1/8 200% of this is -1/4
Step-by-step explanation:
Answer: This type of sampling is Simple Random Sampling
d. Adjustments
Studen loan interests and IRA contributions are deductions found under the heading of ADJUSTMENTS TO INCOME to compute for the Adjusted Gross Income or AGI.
Standard deductions are those based on the filing status of the individual and not his total itemized deductions. Regardless of the actual expenses incurred by an individual, he can claim a standar deduction if he is single, head of household, married filing separately, married filing jointly, qualifying widow(er). at the time he files for his federal tax return.
taxable income is the income left from all the necessary deductions.
For example: Gretchen's income => $56,750
less: Adjustments to income
student loan interest $1,200
IRA Contribution 3,000 - 4,200
===========
Taxable income $52,550
Answer:
a) Null hypothesis:
Alternative hypothesis:
b)
(1)
Replacing we got:
The p value for this case would be given by:
c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%
Step-by-step explanation:
Information given
n=400 represent the random sample taken
X=52 represent the workers belonged to unions
estimated proportion of workers belonged to unions
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
represent the p value
Part a
We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:
Null hypothesis:
Alternative hypothesis:
Part b
The statistic is given by:
(1)
Replacing we got:
The p value for this case would be given by:
Part c
For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%