Answer:
Slope = 
Equation of the line → 
Step-by-step explanation:
Let the equation of diagonal OA is,
y = mx + b
Here, m = Slope of the line OA
b = y-intercept
Slope of a line passing through two points
and
is given by,
m = 
Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,
m = 
m = 
Since, line OA is passing through the origin, y-intercept will be 0.
Therefore, equation of OA will be,

Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
The value of x is 5
Explanation
Given <ACD=2x+4
<ACB=5x-11
Given that ABCD is a rhombus. So the opposite angles will be same and all the sides will be equal.

diagonal AC divides the rhombus into two triangles ACD and ACB
according to angle sum property, the sum of all angles of a triangle is 180.
consider triangle ACD

Answer:9+x=4
Step-by-step explanation:idk how to explain just trust me