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2 years ago

PLEASE HELP ASAP, CORRECT ANSWER GETS BRAINLIEST

Mathematics

2 answers:

Alinara [238K]2 years ago

6 0

A: the initial price of the used car
b: decreasing percent (decay ratio in decimal)
x: number of years
y: the value of car at a given year
$y=a(1-b)^x\\~\\~\\y=15250(1-0.075)^x\\~\\~\\y=15250(0.925)^x$

That is for part 1

Part 2:
after 8 years
plug in x=8 into the equation that we've just formed
 $y=15250(0.925)^8$

and do you math...

I hope that helps!

I am with you if you faced any difficulties!

Fynjy0 [20]2 years ago

4 0

Car value at the time of purchase $15, 250 (2012)
Rate of depreciation 7.5%
1) y = 15250 ( 1- 0.075)^x
y = 15250 (0.925)^x (x tis the number of years that passed since purchase)

2) y = 15250 * ( 0.925)^8 = 8173.42

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The Taieri Plain in New Zealand is 6 feet below sea level (or –6 feet). If you are standing 3 feet above sea level, is your elev

Anna11 [10]

You would be 3ft above the sea level, if you are -6ft under the sea level and if you are standing 3ft “above” you would have to clime back up 9ft to get back to the positive’s which is “positive 3” so yes, your elevation will be opposite of the “plain” since you went to a -6 to a positive 3, with different numbers.

8 0

1 year ago

A row of tiny red beads is placed at the beginning and at the end of a 20‐centimeter bookmark.

AlladinOne [14]

Answer:

51 rows

Step-by-step explanation:

Given

Length of bookmark = 20cm

Distance between beads = 4mm

Required

Number of rows of beads

First, the distance between the rows of beads must be converted to cm

if 1mm = 0.1cm

then

4mm = 4*0.1cm

4mm = 0.4 cm

This means that each row of beads is placed at 0.4 cm mark.

The distance between each row follows an arithmetic progression and it can be solved as follows;

$T_n = a + (n-1)d$

Where $Tn = 20cm$ (The last term)

$a = 0 cm$ (The first term)

$d = 0.4cm$ (The distance between each row of beads)

n = ?? (number of rows)

Solving for n; we have the following;

$T_n = a + (n-1)d$ becomes

$20 = 0 + (n-1)0.4$

$20 = (n-1)0.4$

DIvide both sides by 0.4

$\frac{20}{0.4} = \frac{(n-1)0.4}{0.4}$

$50 = (n-1)$

$50 = n-1$

Add 1 to both sides

$50 + 1= n-1 + 1$

$n = 51$

Hence, the number of rows of beads is 51

4 0

2 years ago

Mr. Johnson currently has a square garden. It is in his garden and into a range of 5 feet shorter than three times shorter than

Vlad [161]

Answer:

The Dimension of new garden is $25 \ feet\ \times 10\ feet.$

Step-by-step explanation:

Given:

Perimeter of new garden = 70 feet.

Let the length of the new garden be 'l'.

Also Let the width of the new garden be 'w'.

We need to find the dimension of new garden.

Now Given:

Length is 5 feet shorter than three times it width.

framing the equation we get;

$l =3w-5 \ \ \ \ equation\ 1$

Now we know that;

Perimeter of rectangle is equal to twice the sum of length and width.

framing in equation form we get;

$2(l+w)=70$

Now Diving both side by 2 using Division property of equality we get;

$\frac{2(l+w)}2=\frac{70}{2}\\\\l+w =35$

Now Substituting equation 1 in above equation we get;

$3w-5+w=35\\\\4w-5=35$

Adding both side by 5 Using Addition Property of equality we get'

$4w-5+5=35+5\\\\4w=40$

Now Diving both side by 4 using Division property of equality we get;

$\frac{4w}{4}=\frac{40}{4}\\\\w=10\ ft$

Now Substituting the value of 'w' in equation 1 we get;

$l =3w-5\\\\l =3\times10-5\\\\l = 30-5\\\\l= 25\ ft$

Hence The Dimension of new garden is $25 \ feet\ \times 10\ feet.$

3 0

2 years ago

Brett’s teacher observed Brett’s behavior in class for a week and compared the minutes he stayed on task in class to the grade h

zhenek [66]

Answer:

positive correlation, likely causal

Explanation:

Correlation and causation are different.

Correlation means that the variables are related, meaning that when one changes the other also change. A positive correlation means that the variables change in the same way: when one increases the other also increases, and when one decreases the other also decreases. A negative correlation means that the variables change in opposite directions, i.e. when one increases the other decreases.

The correlations may be strong, moderated or weak. The correlation coefficient tells how strong the correlation is. The correlation coefficient may take values from - 1 to + 1.

A negative 1 correlation coefficient means a perfect negative correlation. A positive 1 correlation coefficient means a perfect positive correlation. Thus, in this case Brett's teacher found that the correlation coefficent was r = 0.97. That is pretty close to 1, and means that this is a strong positive correlation.

About causation, you only may feature a relationship as causal if one variable is the reason why the other variable changed in the way it did it. In this case, it is very reasonable to attribute a causation relationship between the minutes Brett stayed on task in class and the grade he earned on the homework that night, because the more Brett worked in class the better prepared he should be to do his homework, and that idea is reinforced by the high positive correlation coefficient r = 0.97. That is why you can assert that the teacher must have discored a positive correlation, likely causal.

8 0

2 years ago

Read 2 more answers

What is the binomial expansion of (x + 2)4? x4 + 4x3 + 6x2 + 4x + 1 8x3 + 24x2 + 32x x4 + 8x3 + 24x2 + 32x + 16 2x4 + 8x3 + 12x2

Margaret [11]

Answer-

$\boxed{\boxed{(x+2)^4=x^4+8x^3+24x^2+32x+16}}$

Solution-

Given expression is $(x+2)^4$

Applying Binomial Theorem

$\left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

Here,

a = x, b = 2 and n = 4

So,

$\left(x+2\right)^4=\sum _{i=0}^4\binom{4}{i}x^{\left(4-i\right)}\cdot \:2^i$

Expanding the summation

$=\dfrac{4!}{0!\left(4-0\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(4-1\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(4-2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(4-3\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(4-4\right)!}x^0\cdot \:2^4$

$=\dfrac{4!}{0!\left(4\right)!}x^4\cdot \:2^0+\dfrac{4!}{1!\left(3\right)!}x^3\cdot \:2^1+\dfrac{4!}{2!\left(2\right)!}x^2\cdot \:2^2+\dfrac{4!}{3!\left(1\right)!}x^1\cdot \:2^3+\dfrac{4!}{4!\left(0\right)!}x^0\cdot \:2^4$

$=1\cdot x^4\cdot \:1+4\cdot x^3\cdot \:2+6x^2\cdot \:4+4\cdot x\cdot \:8+1\cdot 1\cdot \:16$

$=x^4+8x^3+24x^2+32x+16$

4 0

2 years ago

Read 2 more answers