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2 years ago

A trapezoid with an area of 166.75 in has bases that measure 21 in and 8 in find the height of the trapezoid

2 answers:

7 0

The formula for the area of a triangle is A= (a+b/2)•h. We substitute in the values we know to find h, which is the height:

•166.75= (21+8/2)•h. Add 21 and 8 so you can simplifying the fraction.
•166.75= (29/2)•h. Divide 29 by 2.
•166.75= 14.5h. Divide both sides by 14.5 so you can get h by itself.
•h=11.5.

The height of the trapezoid is 11.5 inches.

Evgen [1.6K]2 years ago

3 0

Answer:

Step-by-step explanation:

So we know the formula of the area of a trapezoid is base 1 plus base 2 times the height divided by 2.

To find the height you must add the both bases and then divided it by two, and then you divided it by 166.75.

Here is the equation:

21+8/2=14.5 14.5x=166.75

Your answer is 11.5

Hope this answer helps you solve other problems like this.

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5,340

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2 years ago

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The equation y = 14x represents the number of pages Printer A can print over time, where y is the number of pages and x is time

Crank

Printer A
y = 14x

Printer B
Time(min) | 3 | 5 | 8 | 12 |
Pages printed | 48 | 80 | 128 | 192 |

Printer A prints 14(1) = 14 pages per minute.
Printer B prints 48/3 = 16 pages per minute.

The printer that prints at a faster rate is printer B.

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1 year ago

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Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist

Lera25 [3.4K]

Answer:

$Sum = -81$

Step-by-step explanation:

See the comment for complete question.

Given

$c = 36$ ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

$x^2 + ax + 36 = 0$

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

$x = -\alpha$ and $x = -\beta$

Using the above roots, the equation can be represented as:

$(x + \alpha)(x + \beta) = 0$

Open brackets

$x^2 + (\alpha + \beta)x + \alpha \beta = 0$

To compare the above equation to $x^2 + ax + 36 = 0$ , we have:

$a = \alpha + \beta$

$\alpha \beta = 36$

Where: $\alpha, \beta$ and $\alpha \ne \beta$

The values of $\alpha$ and $\beta$ that satisfy $\alpha \beta = 36$ are:

$\alpha = -1$ and $\beta = -36$

$\alpha = -2$ and $\beta = -18$

$\alpha = -3$ and $\beta = -12$

$\alpha = -4$ and $\beta = -9$

So, the possible values of a are:

$a = \alpha + \beta$

When $\alpha = -1$ and $\beta = -36$

$a = -1 - 36 = -37$

When $\alpha = -2$ and $\beta = -18$

$a = -2 - 18 = -20$

When $\alpha = -3$ and $\beta = -12$

$a = -3 - 12 = -15$

When $\alpha = -4$ and $\beta = -9$

$a = -4 - 9 = -13$

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

$Sum = -37 -20 -15 - 9$

$Sum = -81$

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1 year ago

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2 years ago

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1 year ago

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