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PtichkaEL [24]
2 years ago
9

A trapezoid with an area of 166.75 in has bases that measure 21 in and 8 in find the height of the trapezoid

Mathematics
2 answers:
frosja888 [35]2 years ago
7 0
The formula for the area of a triangle is A= (a+b/2)•h. We substitute in the values we know to find h, which is the height:

•166.75= (21+8/2)•h. Add 21 and 8 so you can simplifying the fraction.
•166.75= (29/2)•h. Divide 29 by 2.
•166.75= 14.5h. Divide both sides by 14.5 so you can get h by itself.
•h=11.5.

The height of the trapezoid is 11.5 inches.
Evgen [1.6K]2 years ago
3 0

Answer:


Step-by-step explanation:

So we know the formula of the area of a trapezoid is base 1 plus base 2 times the height divided by 2.

To find the height you must add the both bases and then divided it by two, and then you divided it by 166.75.

Here is the equation:

21+8/2=14.5 14.5x=166.75

Your answer is 11.5

Hope this answer helps you solve other problems like this.

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The quotient of the sum of 2t and 2, twice the cube of s
natali 33 [55]

Answer: \frac{2t+2}{2s^3}

Step-by-step explanation:

Since you did not indicate what you need to do, I assume that you have to write an expression using the sentence given in the problem.

In order to solve this exercise, it is importat to remember the following information:

1. The quotient is the result of a division.

2. The sum is the result of an addition.

3. The word "twice" indicates a multiplicatio by 2.

4. The word "cube" indicates an exponent 3.

Then, keeping on mind the explained above and the data given in the exercise, you know that:

-The sum of 2t and 2 can be expressed as:

2t+2

- Twice the cube of s can be expressed in the following form:

2s^3

Therefore, you can dermine that "the quotient of the sum of  2t and 2 and twice the cube of s" is represented with the following expression:

\frac{2t+2}{2s^3}

O

8 0
1 year ago
In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?
vaieri [72.5K]

Answer:

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And  Cos B = \frac{CB}{AB}.

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

                               Hypotenuse = AB\\Base = CB\\Perpendicular = AC

So,                            Sin\theta = \frac{perpendicular}{hypotenuse}

                                SinB = \frac{AC}{AB}

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

                               SinA= \frac{CB}{AB}

Again,                    Cos\theta= \frac{base}{hypotenuse}

Then,                    CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

Hence,

All trigonometric Ratios are  SinB = \frac{AC}{AB} ,  SinA= \frac{CB}{AB} ,  CosA= \frac{AC}{AB}

And                      Cos B = \frac{CB}{AB}.

                               

8 0
2 years ago
A store manager wishes to reduce the price on her fresh ground coffee by mixing two grades. If she has 35 pounds of coffee which
kari74 [83]

35 lbs, your welcome even though you probably don't need the answer anymore

8 0
1 year ago
Read 2 more answers
Jerry goes to the bank and borrows $9,000 for farm equipment. The simple yearly interest is 9.5% and he pays off the loan over a
creativ13 [48]
To solve this problem you must appply the formula for simple interest, which is:
 
 I = RxPxN
 
 I: Simple Interest.
 R:Rate (9.5$/100=0.095/12).
 P: The principal (P=$9000).
 N:number of periods (N=24).
 
 When you substitute these values into the formula, you obtain:
 
 I=RxPxN
 I=(0.095/12)x9000x24
 I=$1710
 
 Therefore, the monthly payment is:
 
 $1710/24=$71.25
 
 What is Jerry's monthly payment?
 
 The answer is: Jerry's monthly payment is $71.25

4 0
2 years ago
A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Find the lengths of the median o
nexus9112 [7]

Answer:

5/2units\\.

\sqrt{47/2}units \\.

\sqrt{41/2}units\\.

Step-by-step explanation:

The given points are A(1,2,3), B(-2,0,5) and C(4,1,5). The triangle is represented in the attach file where the three possible median are length AE, BF, and CD. We determine the coordinate of point D,E and F using the midpoint equation which is for any point A(x,y,z) and point B(a,b,c), the midpoint D is determine by

D=(\frac{x+a}{2},\frac{y+b}{2},\frac{z+c}{2})\\.

Hence going by the above formula we determine the coordinate of point D,E and F

D=(\frac{-2+1}{2},\frac{0+2}{2},\frac{5+3}{2})\\.

D=(\frac{-1}{2},1,4)\\.

point E

E=(\frac{4-2}{2},\frac{1+0}{2},\frac{5+5}{2})\\.

E=(1,\frac{1}{2},5)\\.

Point F

F=(\frac{4+1}{2},\frac{1+2}{2},\frac{5+3}{2})\\.

F=(\frac{5}{2},\frac{3}{2},4)\\.

To determine the length of each median line we use the formula for distance between two points which is express as

AB=\sqrt{(y_{2}-y_{1} )^{2} +(x_{2}-x_{1} )^{2}+(z_{2}-z_{1} )^{2}} \\.

Using the above formula we determine the length of line AE,BF and CD.

AE=\sqrt{(1-1 )^{2} +(1/2-2)^{2}+(5-3 )^{2}} \\.

AE=\sqrt{0 +9/4+4} \\.

AE=\sqrt{25/4} \\.

AE=5/2units\\.

For point BF

BF=\sqrt{(5/2+2 )^{2} +(3/2-0)^{2}+(4-5 )^{2}}\\.

BF=\sqrt{81/4 +9/4+1} \\.

BF=\sqrt{47/2} \\.

BF=\sqrt{47/2}units \\.

For point CD

CD=\sqrt{(-1/2-4 )^{2} +(1-1)^{2}+(4-5 )^{2}}\\.

BF=\sqrt{81/4 +0+1} \\.

BF=\sqrt{41/2} \\.

BF=\sqrt{41/2}units\\.

7 0
1 year ago
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