Hey
So my brother posted this on Yahoo
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm.
<span>What you do now is the following: </span>
<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>
<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>
<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>
<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>
<span>b) </span>
<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>
Hoped it Helped
Answer:
-12x - 9xy
Step-by-step explanation:
-3x(4x - 5xy + 8y)
distribute
-12x + <u>15xy - 24xy</u>
combine like terms
-12x - 9xy
Answer:
900cm^3
Step-by-step explanation:
1 cm= 10 mm
x=300mm (criss cross)
1cm*300mm/10mm= 10mm*x/10mm
30cm=x
30cm=300mm
1m=100cm
0.2m=x
1m*x/1m=0.2m*100cm/1m
x=0.2*100cm
x=20cm
0.2m=20cm
l=15cm
w=30cm
h=20cm
v=l*w*h
v=15cm*30cm*20cm
v=450cm^2*20cm
v=900cm^3
First, plug in -3 for the y value.
-3=2x²-10x
Then, add 3 to both sides.
0=2x²-10x+3
Use the quadratic equation to solve
(-b+-√b²-4ac)/2a
You get 4.68 or 0.32
You still have to check your answer to see if there is an excluded value.
Both values check.