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Black_prince [1.1K]
1 year ago
13

Which of the following is a validation of congruency between two polygons?

Mathematics
2 answers:
yawa3891 [41]1 year ago
6 0

Answer:

The correct answer is: C) if by applying rigid motions you can make them coincide

Step-by-step explanation:

Two polygons are said to be congruent or identical in form, if they have exactly the same size and shape or if their corresponding angles and sides are also equal. When a rigid motion like - reflection, rotation and translation is applied on the polygons and they maintain the same length and shape then, they are congruent.

iris [78.8K]1 year ago
5 0
I think the correct answer would be C. A validation of congruency between two polygons would be that  if by applying rigid motions you can make them coincide. Two figures are said to be congruent if and only if these figures have the same shape and the same size. All of their sides and angles are the same. Rigid motion is a motion done to a figure that preserves distance or length. If all the rigid motions like rotation, reflection, translation and glide reflection are done and the figures are the same or the lengths are preserved, then the polygons should be congruent.
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Can someone help me on question 14. Please show steps
zavuch27 [327]

Answer:

0.5a+7.5b^2

Step-by-step explanation:

4b^2+3.5a-2a+3.5b^2-a

Group similar terms together:

3.5a-2a-a+4b^2+3.5b^2

Add the term b^2:

3.5a-2a-a+7.5b^2

Subtract the term a:

0.5a+7.5b^2

5 0
1 year ago
A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17).
julia-pushkina [17]

Answer:

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A (V_{1}) = 0.33

Variance of activity B (V_{2}) = 0.67

Variance of activity C (V_{3}) = 0.33

Variance of activity D (V_{4}) = 0.17

Thus the standard deviation on the critical path (\alpha ^{2}) = V_{1} ^{2} + V^2_{2} +  V^2_{3} + V^2_{4}

                                                                             \alpha ^{2}  = 0.33^{2} + 0.67^{2} + 0.33^{2} + 0.17^{2}

                                                                             \alpha ^{2} = 0.6956

                                                                             \alpha = 0.834

The standard deviation on the critical path = 0.834

4 0
1 year ago
Find the volume of the following solid figure. Use = 3.14. V = 4/3r3. A sphere has a radius of 3.5 inches. Volume (to the neares
Juli2301 [7.4K]
To solve the problem shown above, you must apply the proccedure shown below:

 1. You must use tthe formula for calculate the volume of a sphere, which is:

 V=4πr³/3

 V is the volume of the sphere.
 r is the radius of the sphere (r=3.5 inches)

 2. When you susbstitute these values into the formula shown above, you obtain the volume of the sphere. Therefore, you have:

 V=4πr³/3
 V=4π(3.5 inches)³/3

 3. Therefore, the answer is:

 V=179.5 inches³
4 0
1 year ago
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Which of the following is the graph of y = negative 4 StartRoot x EndRoot?
weeeeeb [17]

Answer:

Use a graphing calculator.

Step-by-step explanation:

Graph:

f(x) = -4√x

6 0
2 years ago
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The chart below lists the original and sale prices of items at a clothing store.
Tom [10]

Answer: C) For every original price, there is exactly one sale price.

For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.

As the table shows, we do not have any repeated original prices leading to different sale prices.

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1 year ago
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