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Olenka [21]
2 years ago
14

Box 1: Dimensions: x by 3x by x3 Area of base = x(3x) = 3x2 Box 2: Dimensions: x by 4x – 1 by x3 Area of base = x(4x – 1) = 4x2

– x Complete the statements about the number of terms in the polynomial representing the volume of each box. Box 1's volume will be a Box 2's volume will be a . Explain your reasoning.
Mathematics
2 answers:
NeTakaya2 years ago
6 0

Answer:

1. Monomial

2. Binomial

Step-by-step explanation:

Box 1’s volume is modeled by a monomial times a monomial, so it will be a monomial.  Box 2’s volume is modeled by a monomial times a binomial, so it will be a binomial.

On Edgenuity

andriy [413]2 years ago
4 0

Answer:

box 1: monomial

box 2: binomial

Step-by-step explanation:

reasoning: Box 1’s volume is modeled by a monomial times a monomial, so it will be a monomial.

Box 2’s volume is modeled by a monomial times a binomial, so it will be a binomial.

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give two examples that show how using parentheses can change the order in which operations are performed in an expression?
VMariaS [17]
<span><span>Problem<span>Simplify 3 + 5 </span>•<span> 2.</span>  </span><span> <span>3 + <span>5 </span></span>•<span> 2</span>  <span>Order of operations tells you to perform multiplication before addition. </span> </span><span> 3 + 10 Then add. </span><span>Answer     </span><span>3 + 5 </span>•<span> 2 = 13</span></span>

 

 

 

<span>Example<span>ProblemSimplify 20 – 16 ÷ 4.  </span><span> <span>20 – 16 ÷ 4  </span><span>Order of operations tells you to perform division before subtraction. </span> </span><span> <span>20 – 416</span>Then subtract. </span><span>Answer     </span>20 – 16 ÷ 4 =<span> 16</span></span>
6 0
2 years ago
Find the correct sum of each geometric sequence.
Alex777 [14]
A geometric sequence with first term "a" and common ratio "r" has "nth" term:

ar^(n-1)

And the sum of a geometric sequence with "n" terms, first term "a," and common ratio "r" has the sum "a(r^n - 1)/r - 1.

1.) 765

2.) 300

3.) 1441

4.) 244

5.) 2101
5 0
2 years ago
Read 2 more answers
Ahmed doubled his savings, then deposited another hundred dollars. Let s represent the amount he originally had in savings. Whic
Alex777 [14]
Do the opposite of what you did in reverse order.

so add 100 and divide by 2 in that order.

(80 + 100)/2
3 0
2 years ago
Read 2 more answers
For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
nikitadnepr [17]
Year         Sam              Sally1:             X                    (3/2)X-10002:            (5/2)X-2000     2X-15003:             X/5+1000       X/4+1400Total         37X/10-1000    15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.
6 0
1 year ago
Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
GuDViN [60]

Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Consider the given matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B is

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is given that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

On comparing corresponding elements of both matrices, we get

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Therefore, the required values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

3 0
1 year ago
Read 2 more answers
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