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Bogdan [553]
1 year ago
5

Many urban zoos are looking at ways to effectively handle animal waste. One zoo has installed a facility that will transform ani

mal waste into electricity. To estimate how many pounds of waste they may have to fuel the new facility they began keeping meticulous records. They discovered that the amount of animal waste they were disposing of daily is approximately Normal with a mean of 348.5 pounds and a standard deviation of 38.2 pounds. Amounts over 350 pounds would generate enough electricity to cover what is needed to for the entire aquarium that day. Approximately what proportion of the days can the zoo expect to obtain enough waste to cover what is needed to run the entire aquarium for the day?
(A) 0.484
(B) 0.499
(C) 0.516
(D) 0.680
(E) 0.950
Mathematics
1 answer:
Zolol [24]1 year ago
8 0

Answer: The correct answer is (A).

Step-by-step explanation:

Let X = the amount of waste produced in a given day. X follows a distribution that is approximately Normal with a mean of 348.5 pounds and a standard deviation of 38.2 pounds.

P(X > 350) = Normalcdf(lower: 350, upper: 1000, mean: 348.5, SD: 38.2) = 0.484.

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Explain what you can tell just by comparing the symbols in a picture graph
IceJOKER [234]

The <em>correct answer</em> is:

What objects we're comparing.

Explanation:

In a picture graph, symbols are used to represent the data being displayed. For example, if we took a survey on the types of foods people preferred at a cookout, we could use a picture of a hamburger, a picture of a hot dot and a picture of a chicken leg.

We cannot tell anything about the amounts in the graphs just by comparing the symbols.

5 0
1 year ago
Read 2 more answers
A fisherman is interested in whether the distribution of fish caught in Green Valley Lake is the same as the distribution of fis
maks197457 [2]

Answer:

p = 0.293

Conclusion:

"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."

Step-by-step explanation:

------------R/trout--O/trout---bass--catfish---total

GVL - - - 105 - - - 27 - - - - - 35--- 24 - - - 191

EL - - - - 135------- 48-------- 67 - - 43 - - - 293

Total - - 240 - - - 75 - - - - - 102--- 67 - - - 484

Note : GVL = GREEN VALLEY LAKE ; EL = ECHO LAKE.

H0: The distribution of fish caught in green valley is the same as that caught in Echo lake.

H1: The distribution of fish caught in Green Valley lake is different from that caught in Echo valley lake.

Using the chi-squared test statistic calculator ;

χ2 = 3.7269

p-value = 0.2925.

p-value = 0.293

Conclusion:

"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."

5 0
1 year ago
1. The speed at which an automated assembly line produces a product follows a normal distribution with mean production time of 3
strojnjashka [21]

Answer: Probability = 0.2

Step-by-step explanation:

Given data:

Mean production time = 32.20 seconds

Standard deviation = 1,05seconds

probability that a full production run will take less than 32 seconds on average to produce

= P(Xbar<32)

= P(Z<-0.8518)

= 0.2

8 0
1 year ago
the mean length of 7 books is 258 pages . the longest book has 294 pages. what is the mean length of the other 6 books
den301095 [7]
I think you divide.. find the mean of all of the numbers?
8 0
2 years ago
Find the 89th term of 25,35,45
MAXImum [283]

Answer:

The 89th term would be 895.

Step-by-step explanation:

There is a pattern of adding 10 each time. Notice that the 5 at the end doesn't change and that the first number continues (i.e. 2, 3, 4, 5, 6). All you have to do is add an 89 in front of the 5 and that is your answer, 895.

4 0
1 year ago
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