Three highways connect city A with city B. Two highways connect city B with city C.
1 answer:
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:
β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:
β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
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Answer: $ 4,515
Step-by-step explanation:
The cost of the car she wanted to buy = $35,550
Her savings = $20,700
That means she needs( $35,550 - $20,700) more in order for her to buy the car.
Amount borrowed from the finance company = $35,550 - $20,700
= $ 14,850
Since she now owes the financial company a total of $19,365, then the interest accrued by the loan she borrowed is given by:
$19,365 - $ 14,850
= $4,515
Answer:
The probability that the man is greater than 74 inches is 0.1587
Step-by-step explanation:
The required probability is found by evaluating the area under the corresponding distribution curve for the corresponding values
The standard normal variate factor (Z) is given by
where
is mean of the data
is the standard deviation of the data
Thus corresponding to x = 74 the Z factor equals
Using the standard normal distribution table corresponding to mean of 70 and deviation of 4 the area under the curve corresponding to Z = 1 equals
0.1587