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m_a_m_a [10]
2 years ago
12

What is the simplified value of the expression below rounded to the nearest hundredth? StartFraction 3.5 times 2 + 9 over 10.4 m

inus 1.4 times 2 EndFraction 0.28 0.89 1.91 2.11
Mathematics
1 answer:
miskamm [114]2 years ago
7 0

Answer:

The answer is 2.11~! I hope I helped <3

Step-by-step explanation:

3.5x2=7   7+9=16   1.4x2=2.8   10.4-2.8=7.6   16/7.6=2.10526315789

but we simplify so, 2.10526315789 rounded to the nearest hundredth is 2.11~!

 

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Answer: parabola

Step-by-step explanation:

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You research the average cost of whole milk for several recent years to look for trends. The table shows your data. What is the
Rashid [163]

The <em>correct answers</em> are:

y = 0.10x + 2.50; $5.

Explanation:

Using a graphing calculator, we enter the data in the STAT function. The year will be the independent (x) variable and the cost will be the dependent (y) variable.

For the year, instead of starting at 1998, we will start at 0, since that is where we started measuring. This means the year 2000 will be 2; 2002 will be 4; etc, up to x=10.

Running the linear regression, the calculator gives us a slope of 0.10 and a y-intercept of 2.499, or 2.50. This makes the equation y = 0.10x + 2.50.

To predict the price in 2023, we first find what our x-value will be. Subtract 1998 from this:

2023-1998 = 25

Now substitute 25 in place of x in the equation:

y = 0.10(25) + 2.50 = 2.50 + 2.50 = 5

5 0
2 years ago
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S_A_V [24]

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L(w) = 8 mm + (2 mm/wk)(wk)

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Answer:

The ant Fidencia ate more

Step-by-step explanation:

The question in English

The ant Fidencia found a leaf, the charge and took the anthill. She gave her friend 1/5 and she ate 1/3 of the leaf. Who ate more?

Her friend

Multiply (1/5) by (3/3)

(1/5)*(3/3)=3/15

Ant Fidencia

Multiply (1/3) by (5/5)

(1/3)*(5/5)=5/15

Compare

5/15 > 3/15 -----> two fractions with the same denominator the fraction with the highest numerator is greater

therefore

The ant Fidencia ate more

7 0
2 years ago
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
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