Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7
890×(1+0.187÷12)^(12)−890×(1+0.125÷12)^(12)=63.61....answer
I was able to find the image associated with this question, in which the coordinates of point Z are given as (-2,-1).
We know that the coordinates of a point are multiplied by the scale factor to give the new coordinates. Since these coordinates result after the dilation, we divide them by the scale factor to obtain the original coordinates as such:
-2/0.25 , -1/0.25
(-8 , -4)
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0