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2 years ago

An office uses 478 lb of paper in one week. The paper comes in packages that hold 18 lb of paper each.

2 answers:

7 0

To figure this out, we must divide the amount of pounds of paper they use in one week by the amount of pounds of paper in each package.

478 / 18 = 26.555556

So there's your answer, 26.5 packages.

Hope this helps! :)

Lana71 [14]2 years ago

4 0

They use about 26.56 packages of paper in a week.

You might be interested in

Explain how you can find 3x584 using expanded form

nasty-shy [4]

I believe what you need to do is multiply 3 by each number.
To start, 3*584 is 1752. Expanded form written out would be (3*500)+(3*80)+(3*4). Simply multiply all the numbers and then add them together. 3*500=1,500; 3*80=240; 3*4=12. 1,500+240=1740+12=1752. Hope this helps! :)

5 0

2 years ago

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig

Keith_Richards [23]

Answer:

1. Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

We need to find the mean for each group first and the grand mean.

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

If we apply the before formula we can find the mean for each group

$\bar X_A = 27$ , $\bar X_B = 24$ , $\bar X_C = 30$ . And the grand mean $\bar X = 27$

Now we can find the sum of squares between:

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

Each group have a sample size of 4 so then $n_j =4$

$SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72$

The degrees of freedom for the variation Between is given by $df_{between}=k-1=3-1=2$ , Where k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

$MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36$

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

$SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306$

And the degrees of freedom are given by:

$df_{within}=N-k =3*4 -3 = 12-3=9$ . N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

$MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34$

C. 34

Part 4

The test statistic F is given by this formula:

$F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059$

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is $F_{crit}=8.02$

B. 8.02

5 0

2 years ago

Franklin rides his bike to the beach averaging 18mph. He rides home along the same route. What speed must he average on the way

Sedaia [141]

Answer:

24 mph

Step-by-step explanation:

Hi there !

Vm = 21mph

V1 = 18mph

V2 = ?

Vm = (V₁ + V₂)/2

2Vm = V₁ + V₂

V₂ = 2Vm - V₁

replace Vm ; V₁

V₂ = 2×21mph - 18mph

= 42mph - 18mph

= 24 mph

Good luck !

8 0

2 years ago

Sitting on a park bench, you see a swing that is 100 feet away and a slide that is 80 feet away. The angle between them is 30 de

leva [86]

We are given : Distance of the swing = 100 feet.

Distance of slide = 80 feet.

Angle between swing and slide = 30 degrees.

We need to find the distance between the swing and the slide.

Distance of swing, distance of slide and distance between the swing and the slide form a triangle.

We can apply cosine law to find the distance between the swing and the slide.

c^2 = a^2 +b^2 - 2ab cos C

c^2 = 100^2 +80^2 - 2(100)(80) cos 30°

c^2 = 10000 + 6400 -2* 8000 $(\frac{\sqrt{3}} 2)}$

c^2 = 16400 - 8000 $\sqrt{3}$

c^2 = 16400 - 13856

c^2 = 2544

$c =\sqrt{2544}$

c= 50.44

c = 50 feet approximately.

<h3>Therefore, the approximate distance between the swing and the slide is 50 feet.</h3>

5 0

2 years ago

Read 2 more answers

Is ABC~DEF? If /so, identify the similarity postulate or the theorem that applies, A. similar- AA B. similar-SSS C. similar- SAS

Mariana [72]

Answer: Similar - AA

Just took the quiz, Its Similar AA not sure why just trust me homie

3 0

2 years ago