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Nataly_w [17]
2 years ago
15

The solid graph is a translation of RootIndex 3 StartRoot x EndRoot. On a coordinate plane, 2 cube root functions are shown. The

first has equation f (x) and is represented by a dashed line. It goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes through (8, 2). The second function goes through (negative 8, 0), has an inflection point at (0, 2), and goes through (8, 4). How was the graph of RootIndex 3 StartRoot x EndRoot shifted to form the translation? 2 units up 2 units down 2 units left 2 units right
Mathematics
2 answers:
Advocard [28]2 years ago
7 0

Answer:

2 units up

Step-by-step explanation:

There is no left or right translation so this makes it easy for us. It clearly shifts two points/units up, so you are automatically finished with this answer!

serious [3.7K]2 years ago
6 0

Answer: 2 units up.

Step-by-step explanation:

If you take a look at the graph, it shows that it is 2 units up from where it initially started, therefore it is moved 2 units up. It says the SOLID graph is the translation, therefore it would be moving 2 units up.

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Which of the following could be the system of nonlinear inequalities graphed below?
Ivan

Answer:

Option A.

Step-by-step explanation:

step 1

we know that

The equation of the solid line is

y=5

The solution is the shaded area above the solid line

so

The equation of the first inequality is

y\geq 5

step 2

The equation of the dashed line is

y=x^{2} -5x+6

The solution is the shaded area above the dashed line

so

The equation of the second inequality is

y>x^{2} -5x+6

therefore

The system of inequalities could be

y\geq 5

y>x^{2} -5x+6

4 0
2 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
2 years ago
The cost to ride on a ferry is $5.00 per vehicle and driver with an additional cost of 50 cents per passenger. if the charge to
Dvinal [7]
5 + 0.50p = 6.50
0.50p = 6.50 - 5
0.50p = 1.50
p = 1.50/0.50
p = 3 <=== the vehicle had 3 people in the vehicle
6 0
2 years ago
Read 2 more answers
Amanda can proofread 17 reports in an hour, while Sally can proofread 28 reports in an hour. If they have 420 reports to proofre
mafiozo [28]

Answer:

9 hours and 20 minutes.

Step-by-step explanation:

In one hour, Amanda can proofread 17 reports.

In one hour, Sally can proofread 28 reports.

That means together, they can proofread 45 reports in one hour.

So we need to divide the total amount of reports by how much they can read in an hour:

420/45 = 28/3 = 9 1/3

The time it takes between the two of them is 9 hours and 20 minutes.

8 0
2 years ago
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One way to solve the system is to _____________ a variable.
Ivahew [28]

One way to solve the system is to <u>substitute</u> a variable.

<u>Explanation:</u>

One approach to solve an equation is by substitution of one variable. Right now, a condition for one factor, at that point substitute that arrangement in the other condition, and explain. All value(s) of the variable(s) that fulfills a condition, disparity, arrangement of conditions, or arrangement of imbalances.

The technique for tackling "by substitution" works by settling one of the conditions (you pick which one) for one of the factors (you pick which one), and afterward stopping this go into the other condition, "subbing" for the picked variable and fathoming for the other. At that point you back-explain for the principal variable.

8 0
2 years ago
Read 2 more answers
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