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Fudgin [204]
2 years ago
8

Gabe and Eugenia bought a house! Their loan is for $117,000 , for 15 years at an annual interest rate of 4% . This results in a

monthly payment of $865.43 . If only the minimum payment is made in month one, how much of the first payment goes toward reducing her balance? First, let's find the amount of interest she paid in month 1
Mathematics
1 answer:
cupoosta [38]2 years ago
4 0

Answer:

Principal element is $475.43

Interest payment is $390

Step-by-step explanation:

The amount of interest paid in month one is 4%*$117,000*1/12=$390

The interest is calculated based on the annual interest rate of 4% apportioned to reflect one month interest by multiplying by 1/12

The principal element of monthly payment is the monthly payment minus interest.

principal paid in month one=$865.43-$390=$475.43

Ultimately,$475.43 goes toward reducing her loan balance while the $390 is interest on loan

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
jenyasd209 [6]

Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
2 years ago
Matthew and his 3 siblings are wedding a flower bed with an area of 9 square yards. If they shared the job equally,how much squa
Tatiana [17]
The answer is 27 yards
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2 years ago
One of the solutions to x2 − 2x − 15 = 0 is x = −3. What is the other solution?
Bond [772]

Answer:x=5

Step-by-step explanation: x^2−2x−15=0

(x−5)=0                                                                                                                        x−5=0                                                                                                                           x=5

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Chuck has a gross pay of $815.70. By how much will Chuck’s gross pay be reduced if he has the following items withheld?
Alex787 [66]

Answer:

273.38

Step-by-step explanation:

815.70 * 6.2% = 50.57

815.70 * 1.45% = 11.83

815.70 * 19% = 154.95

Add those 3 totals to the additional $56 in federal tax

56+50.57+11.83+154.95 = 273.35

5 0
2 years ago
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The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of
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Answer:

x = 8

Step-by-step explanation:

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