The return trip took 1 hour 42 minutes longer
Further explanation:
The distance will remain same on return.
The formula for speed is given by:

Let d be the distance
s1 be the speed while going and s2 be the speed while returning
and
t1 be the time while going and t2 be the time while returning
d=500 miles
s1=60 miles per hour
s2=50 miles per hour
We have to calculate time for both trips,
So,
<u>Time while Going:</u>
<u>
</u>
<u>Putting the values of d and s1</u>
<u>
</u>
<u>Converting 8.3</u>
8 will be the hours,
for 0.3 hour
0.3*60=18 minutes
The first trip took 8 hours and 18 minutes.
<u>Time while returning:</u>

Putting the values of d and s1

The difference of both times is: 1 hour 42 minutes
So,
The return trip took 1 hour 42 minutes longer
Keywords: Time, Distance, Speed
Learn more about movement at:
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ANSWER

EXPLANATION
We want to find the constant that must be added to

to form a perfect square.
Comparing the given expression to

we have
a=1 , b=-3 , and c=0.
We need to add

We substitute the values to get,

We change this to mix numbers to get,

The last choice is correct.
Answer:
$1.46
Step-by-step explanation:
To find the original price of the game, write a proportion. $1.54 is the amount after a 5.5% tax rate. This means he paid 105.5% on the original price.

Find y by cross multiplying numerator and denominator of each fraction.
1.54(100) = 105.5y
154 = 105.5y
1.46 = y
198/6=33
33X5=165, 165 is 5 times of 33.
165+33=198 the sum of 2 odd number 165 & 33 is odd numbers.
33 & 165 is multiple of 3
The formula is
Fv=p [(1+r)^(t)-1)÷r)
Fv ?
P 5000
R 0.075
T 6. June
Fv=5000 [(1+0.075)^(6)-1)÷0.075]
Fv=36220....answer