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irga5000 [103]
2 years ago
8

How do you solve the equation 2/7m-1/7=3/14

Mathematics
1 answer:
photoshop1234 [79]2 years ago
8 0
Add 1/7 to both sides to get 2/7m=3/14+1/7 find common denominater (14) so multipy 1/7 by 2 to get 2/14 than add that to 3/14 to get 5/14 than take 2/7 and 5/14 turn into a decimals than divide the 2/7 on both sides to get m=?
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Which inference is true?
Musya8 [376]

Answer:

The answer is c

I just answered the question on edunity

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What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x
zubka84 [21]

Answer:

[x(x - 1)(x - 4)]/(2(x + 4))

Step-by-step explanation:

We want to find;

[(x² - 16)/(2x + 8)] * [(x³ - 2x² + x)/(x² + 3x - 4)]

Now,

x² - 16 can be factorized as;

(x + 4)(x - 4)

Also, 2x + 8 can be factorized as;

2(x + 4)

Also, (x³ - 2x² + x) can factorized as;

x[x² - 2x + 1] = x[(x - 1)(x - 1)]

Also,(x² + 3x - 4) can be factorized out as; (x - 1)(x + 4)

So plugging in these factorized forms into the equation in the question, we have;

[(x + 4)(x - 4)/(2(x + 4))] * [x[(x - 1)(x - 1)] /((x - 1)(x + 4))

This gives;

((x - 4)/2) * x(x - 1)/(x +4)

This gives;

[x(x - 1)(x - 4)]/(2(x + 4))

8 0
2 years ago
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the trinomial x2 bx c factors to (x m)(x n). if b is negative and c is positive, what must be true about m and n?
galina1969 [7]

For c to be positive, and for b to be negative, m must be negative and n must be negative.


X^2 - bx + c = (x - m)(x - n).

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Tema [17]
Let's call Tacos t and Enchiladas e. 
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Alex paid $12.50 for 3t and 4e.
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4 0
2 years ago
A rectangular sheet of metal has identical squares cut from each corner. The sheet is then bent along the dotted lines to form a
Reika [66]

The <em><u>correct answer</u></em> is:

3 inches.

Explanation:

We will use the Rational Roots Theorem to solve this.

First we can divide both sides of the equation by 4 in order to simplify it:

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In order to solve this, we want the polynomial set equal to 0. To do this, subtract 105 from both sides:

x^3-18x^2+80x-105=105-105 \\x^3-18x^2+80x-105=0

The Rational Roots Theorem says that if p/q is a root of the polynomial, then p is a factor of the constant term and q is a factor of the leading coefficient. The constant term is -105. Drawing a factor tree, we find that the factors of this number are 1, -1, 3, -3, 5, -5, 7, -5, 15, -15, 21, -21. The leading coefficient is 1; its only factor is 1. This means p/q must be a whole number, and can be any of the factors of 105.

Using synthetic division, we try 1 in the box:

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Since there is a remainder, this is not a root. Trying -1,

<u>-1 |</u> 1 -18 80 -105

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1 -19 99 -204

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Trying 3,

3 | 1 -18 80 -105

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1 -15 35 0

Since there is no remainder, 3 is a root, and is the answer we are looking for.

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