14. A $40,000 loan at 4% dated June 10 is due to be paid on October 11. Calculate the amount of interest (assume ordinary intere
2 answers:
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Answer:
The probability of getting a sample with 80% satisfied customers or less is 0.0125.
Step-by-step explanation:
We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.
Let = <u><em>sample proportion of satisfied customers</em></u>
The z-score probability distribution for the sample proportion is given by;
Z = ~ N(0,1)
where, p = population proportion of satisfied customers = 90%
n = sample of customers = 80
Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( 80%)
P( 80%) = P(
) = P(Z
-2.24) = 1 - P(Z < 2.24)
= 1 - 0.9875 = <u>0.0125</u>
The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.
Answer:
The correct option is Mean and standard deviation.
Step-by-step explanation:
The data set provided, arranged in ascending order is:
S = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 4}
Now, it is provided that Macy was absent when the data was collected and the class guessed she had 4 siblings. When she returned, they found out she actually has 9 siblings.
So, the new data set is:
X = {0 , 0 , 0 , 1 , 1 , 1 , 1 , 1 , 1 , 2 , 2 , 2 , 2 , 2 , 2 , 2 , 3 , 3 , 3 , 4 , 9}
The mean of a data set is the average value representing the entire data.
The median is the middle value of the data set.
The inter-quartile range is the difference between the first and the third quartile.
The standard deviation is the value that represents how dispersed the data values are.
From all the above statistic, the mean and standard deviation are the only ones that uses all the observations in the data set to compute their value.
So, on changing one of the 4s by a 9, the set of measures that will be affected are the mean and standard deviation.
Thus, the correct option is Mean and standard deviation.