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Helen [10]
2 years ago
6

What is 63.4 divided by 20

Mathematics
2 answers:
Zanzabum2 years ago
6 0
317 is the answer you are looking for.
atroni [7]2 years ago
6 0

Answer:

3.17

Step-by-step explanation:


63.4/20=3.17


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A. One day Annie weighed 24 ounces more than Benjie, and Benjie weighed 3 1/4 pounds less than Carmen. How did Annie’s and Carme
Debora [2.8K]
<h2>Answer:</h2>

A.

Let Annie's weight be = a

Let Benjie's weighs = b

Let Carmen's weight be = c

One day Annie weighed 24 ounces more than Benjie, equation forms:

a=b+24        ......(1)

Benjie weighed 3 1/4 pounds less than Carmen.  

In ounces:

1 pound = 16 ounces

\frac{13}{4} pounds = \frac{13}{4}\times16=52 ounces

b=c-52  or

c=b+52    ......(2)

Now adding (1) and (2), we get

a+b=b+24+c-52

=> a=c-28

This gives  Annie weighs 28 ounces less than Carmen.

B.

We cannot know anyone's actual weight, as we only know their relative weights.

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2 years ago
Cheyenne and Jacob are geocaching. They are currently hiking on a main trail at a bearing of N 45° E. They determine that the ca
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Answer:

1.8 miles

Step-by-step explanation:

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2 years ago
Georgina has a cube-shaped ring box. The volume of the box is 125 cubic centimeters. What is the length of the box in centimeter
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you need to find one side then see what multiples are equal to your answer
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Eula needs to buy binders that cost $4 each and notebooks that cost $2 each. She has $20. The graph of the inequality 4x + 2y ≤
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2 years ago
Read 2 more answers
Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p
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Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the <em>sampling distribution of sample proportions</em> <em>(p-hat)</em>.

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

0 0
2 years ago
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