Let the width of the yard be w.
Since the length is 18feet longer, l = w + 18
Perimeter for rectangle = 2(l + w)
2(l + w) = 72
2(w+18 + w) = 72 Divide 2 on both sides
(w + 18 + w) = 36
2w + 18 = 36
2w = 36 - 18
2w = 18 Divide 2 on both sides
w = 18/2
w = 9
Recall, length l = w + 18, l = 9 + 18 = 27
Hence width, w = 9, length,l = 27
Area of rectangle = l × w = 27 × 9 = 243
Area of rectangular yard = 243 square feet.
Answer: Barbarino's rentals has a better deal.
She has to drive 887.5 miles to spend the same amount at either company.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
<em>Mr.kotters rentals (A)
</em>
- <em>$99 PER WEEK
</em>
- <em>$0.11per mile over 100 miles
</em>
<em>Barbarino's rentals (B)
</em>
- <em>$75 per week
</em>
- <em>$0.15 per mile over 150 miles
</em>
For "A"
Cost = 0.11 (432-100) + 99 = $135.52
For "B"
Cost= 0.15 (432-150) +75 = $117.3
Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)
To find how many miles would Glenna drive before she would be spending the same amount at either company:
A =B
0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3
Solving for M (miles)
0.11 M -11+99 = 0.15 M -22.5+75
-11 +99 +22.5 -75 =0.15M -0.11 M
35.5 = 0.04M
35.5/0.04 = M
887.5 =M
She has to drive 887.5 miles to spend the same amount at either company.
Mukat gets 40, Usha gets 8
Step-by-step explanation:
Mukat = 5 × Usha
After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)
Then Mukat = final number of books for Usha
5 × Usha - 16 = Usha + 16
(5 × Usha ) - Usha = 16+16
4 × Usha = 32
Usha = 8 i.e her number of books.
Mukat = 5×8=40.
I HOPE IT'S OK
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
