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egoroff_w [7]
2 years ago
8

Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did

each girl have?
Mathematics
1 answer:
vladimir1956 [14]2 years ago
6 0

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

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Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car
Anna35 [415]

Answer:

Patricia will run 132 kilometers with 11 liters of gas.

Step-by-step explanation:

The given table is representing the distance driven by Patricia for every liter of gas she puts in her car.

With 3 liters of gas she drives 36 kilometers.

This means in one liter of gas distance covered by the car = \frac{36}{3}=12 kilometers.

Similarly if the car runs 48 kilometers in 4 liters of gas then per liter distance covered by the gas will be = \frac{48}{4}=12 kilometers

Now with 11 liters of gas distance covered by the car will be = 11×12

= 132 kilometers

Therefore, with 11 liters of gas Patricia can run 132 kilometers.

3 0
1 year ago
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A plumber charges a $45 fee to make a house call and then $25 for each hour of labor. The plumber uses an equation in the form e
sasho [114]
M=slope
In this case the slope would be $25
y=mx+b
y=25x+45

Answer: m=25
5 0
2 years ago
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Triangle A B C is reflected across line m to form triangle A prime B prime C prime. Triangle A prime B prime C prime is rotated
Helga [31]

Answer:

  1. reflection across line m
  2. rotation about point A'

Step-by-step explanation:

The problem statement tells you exactly what the transformations are.

The first transformation is reflection across line m.

The second transformation is rotation about point A'.

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These are both rigid transformations, so ΔABC ≅ A'B''C''.

6 0
1 year ago
The time it takes to deliver a pizza (from time of phone call to delivery at door) follows a normal distribution with a mean (µ)
Yuki888 [10]

Answer:

99.87% of the store’s total delivery orders will be delivered to consumers with charge

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 5

If a pizza store’s policy is, "Orders delivered within one hour or they’re free!", what percentage of the store’s total delivery orders will be delivered to consumers with charge?

Within one hour, which is 60 minutes. So this is the pvalue of Z when X = 60.

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 45}{5}

Z = 3

Z = 3 has a pvalue of 0.9987

99.87% of the store’s total delivery orders will be delivered to consumers with charge

5 0
1 year ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
1 year ago
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