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ss7ja [257]
1 year ago
13

To raise money for a local charity, students organized a wake-a-thon

Mathematics
1 answer:
arsen [322]1 year ago
6 0

Answer:

a) T= 3.125h

b) $75

Step-by-step explanation:

Given: We know Tania raised $50 for staying awake 16 hours. We also know the amount of money raised varies directly with the time.

We can divide $50 into 16 hours.

50/16 = 25/8

25/8 = 3.125

3.125 = 3 1/8 (You can use a fraction or decimal, whichever is preferred)

That's how much money she earns per hour. It may not make sense because you have 1/8 of a dollar, so it's okay if you're a little confused on that.

Now let's answer the first question: Write an equation relating the money Tania raised and the  amount of time, in hours, she stayed awake.

We know Tania earns $3.125 per hour, so we can make it this equation

T= 3.125h

T can represent Tania's earnings, and 3.125 is how much she earns h, hourly.

Now onto the second question: How much would she have raised by staying awake for 24 h?

We need to multiply 3.125, or 3 1/8, 24 times. Your answer should be $75.

(I apologize in advance if I misread something or made a mistake)

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Answer:

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Step-by-step explanation:  My reasoning behind is that 70 percent of the neighborhood wants a playground if it is 40 to 17

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Answer:

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30,45,x,100; The median is 51
Alex Ar [27]
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In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.

So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:

1. Multiply by 2
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2. Subtract 45
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The x value for your question is 57.
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2 years ago
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To solve this problem, we need to plug in 1325 into the y-variable and solve from there.

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And because we cannot go past budget, we will have to round down to 25. In context, the maximum amount of months Abbey can do is 25 months.
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