Ask question

Ask question

All categories

2 years ago

5

Connie keeps her sports card collection in a 54-page book. Each page has 9 slots for cards. Football cards take up the first 18

pages of the book. Use the drop-down menus to describe how many slots in the book may be filled with the baseball cards.

2 answers:

Ierofanga [76]2 years ago

5 0

Answer:

162

Nine time Nine times Two gets you the answer provided

zhuklara [117]2 years ago

5 0

Answer:

the answer is 324

Step-by-step explanation:

You might be interested in

Ava bought some pens for $ 2 each and some pencils for $ 1 each. She bought 3 more pens than pencils and spent a total of $ 12.

Rudiy27

Answer:

Step-by-step explanation:

price of 1 pen= $ 2

price of 1 pencil= $1

total money spent= $12

Let the number of pen be a and number of pencil be b.

2 a + b = 12 ----------------Equation 1

We have, she bought 3 more pens than pencils

a - b = 3 ------------------ Equation 2

Equation 1 +Equation 2,

2 a + b + a - b = 12 + 3

3a = 15

a = 5

Substituting in equation

5 - b = 3

b = 2

Number pencils Ava bought = 2

5 0

2 years ago

Which equation below shows a correct first step for solving 3x = -12

Wewaii [24]

The answer is A. You just solve each one and you would find that it would be the same as 3x=-12.

5 0

1 year ago

Nakita rode her skateboard at an average speed of 8.8 feet per second for 0.2 miles. She wants to calculate how long it took her

timama [110]

Answer: $2\ minutes$

Step-by-step explanation:

We know that:

$d=rt$

Where "d" is distance, "r" is rate and "t" is time.

Solved for the time "t":

$t=\frac{d}{r}$

The first step is to convert the distance from miles to feet.

Since $1\ mile=5,280\ feet$ , we get:

$d=(0.2\ mi)(\frac{5,280\ ft}{1\ mi})\\\\d=1,056\ ft$

Knowing that:

$r=8.8\ \frac{ft}{s}$

We can substitute values into $t=\frac{d}{r}$ in order to find the time in seconds:

$t=\frac{1,056\ ft}{8.8\ \frac{ft}{s}}\\\\t=120\ s$

Since:

$1\ minute = 60\ seconds$

The time in minutes is:

$t=(120\ s)(\frac{1\ min}{60\ s})\\\\t=2\ min$

7 0

2 years ago

If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?

lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

$C = 9 * 10^2kg$

$C = 9 *100kg$

$C = 900kg$

$B = 1.8 * 10^5kg$

$B = 1.8 * 100000kg$

$B = 180000kg$

Divide the bigger weight by the smaller weight

$\frac{B}{C} = \frac{180000kg}{900kg}$

$\frac{B}{C} = \frac{180000}{900}$

$\frac{B}{C} = {200}{}$

Multiply both sides by C

$C * \frac{B}{C} = {200}{} * C$

$B = {200}{} * C$

$B = 200}C$

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

7 0

1 year ago

The formula P = 0.68x2 - 0.048x + 1 models the approximate population P, in thousands, for a species of fish in a local pond, x

marshall27 [118]

Answer:

The answer to your question is 2184

Step-by-step explanation:

Data

Equation P(x) = 0.68x² - 0.048x + 1

x = years

population = 33984

Process

1.- Substitute the population in the equation

33984 = 0.84x² - 0.048x + 1

2.- Equal to zero

0.84x² - 0.048x + 1 - 33984 = 0

3.- Simplify

0.84x² - 0.048x - 33983 = 0

4.- Solve for x

$x = \frac{0.048 +- \sqrt{(0.048^{2}) - (4)(0.84)(-33982)}}{2(0.84)}$

$x = \frac{0.048 +- \sqrt{337.9}}{1.68}$

x1 = 201.2

x2 = -201.2

Only x1 is correct because time can not be negative

5.- Calculate the year

Year = 1997 + 201

Year = 2184

8 0

2 years ago