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Naily [24]
2 years ago
9

The Martin family spent $518 on groceries in one week. What is the average amount the family spent on groceries per day?

Mathematics
2 answers:
lora16 [44]2 years ago
8 0

Answer:

$74

Step-by-step explanation:

Since there are 7 days in a week, we divide 518 by 7

In my journal I worked it out and the answer is 74 hope that helped!

Vaselesa [24]2 years ago
3 0

Answer:

$74

Step-by-step explanation:

518 divided by 7(days in a week)

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Mrs. Dimitri purchased a case of yogurt cups. Out of every 10 yogurt cups, 6 are strawberry.
emmasim [6.3K]

Answer:

1) The fraction of yogurt cups that are strawberry is 18/30. (True)

2) There are a total of 60 strawberry yogurt cups. (False)

3) 60% of the yogurt cups are strawberry. (True)

4) 30% of the yogurt cups are NOT strawberry. (False)

Step-by-step explanation

Total number of yogurt cups are = 30

for every 10, 6 are strawberry

thats is for the whole 30 cups total number of strawberries are = 18

1) The fraction of yogurt cups that are strawberry,

that is the fraction of the total number of strawberries over the total number of cups which is 18/30

2) There are a total of 60 strawberry yogurt cups,

the total number of yogurt cups is 30 while that of strawberry is 18

3) 60% of the yogurt cups are strawberry,

which is 18/30 * 100% = 60%

4) 30% of the yogurt cups are NOT strawberry,

percentage of the remaining cups will be 100% - 60% = 40%

8 0
2 years ago
Luke says you can always add and always multiply to join groups. Is he correct?
dezoksy [38]
Yes, because only equal groups can be multiplied

5 0
2 years ago
Read 2 more answers
Simplify square root of (1-sin theta)(1+sin theta)
Vinil7 [7]
Recall the important identities:

i) (a-b)(a+b)= a^{2}- b^{2}, the difference of squares formula.

ii) sin^{2} x+cos^{2}x=1, for any angle x.

Then,

from i)

\sqrt{(1-sin(theta))(1+sin(theta))}= \sqrt{1- sin^{2}(theta) }

then, from ii), we have 

\sqrt{1- sin^{2}(theta) }= \sqrt{cos^{2}(theta) }=cos(theta)


Answer: cos(theta) 

6 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
2 years ago
Find the range of y=3/2cos4x-1
MrRissso [65]

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1,  y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1,  y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

5 0
2 years ago
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