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abruzzese [7]
2 years ago
9

Elliot collects miniature toy cars. He wants to fill 4 display cases.each display case holds 15 cars. He has 28 cars now, and he

is able to buy 3 more every month with the money he saves from his allowance. How many more months will it be until elliot has enough cars to fill all 4 display cases?
Mathematics
1 answer:
baherus [9]2 years ago
7 0

Answer:

Elliot has to wait 11 months before he has enough cars

Step-by-step explanation:

Elliot has 4 display cases with each case being able to hold 15 cars. Thus we know

total # of cars Elliot can place in his display case = 4 * 15 = 60 cars

From this, we can figure out how many more cars Elliot needs by subtracting the amount of cars he already has

# of cars Elliot needs = 60 - 28 = 32 cars

Now to find the number of months Elliot needs, we divide by how many he can buy each month

# of months Elliot needs to save up for = 32 / 3 = 10 2/3

Assuming Elliot does not get his allowance until the end of the month, we will have to round the number of months up to the nearest integer, 11

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Crude birth rate is all the time reported per 1000 living people.

To compute for this, the formula is number of births x 1000 divided by the estimated population at midyear. So plugging in the values given:

14,662 x 1000 divided by 994,948

= 14662000 / 994948

= 14.68 per 1000 living people.

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What number should go in the space? Multiplying by 1.36 is the same as increasing by _____%.
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136%

Step-by-step explanation:

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Write the polynomial of least degree with roots -2, 5, and 7.
fomenos
For roots of -2, 5, and 7.

x = -2, x = 5, and x = 7

x = -2                        x = 5                             x = 7           

(x + 2) = 0                 (x - 5) = 0                   (x - 7) = 0

The polynomial of least degree would be:
(x -2)(x - 5)(x - 7) = 0

(x -2)(x -5) = x(x - 5) - 2(x -5)
              
                 = x² - 5x - 2x + 10

                 = x² - 7x + 10

 (x² - 7x + 10)(x -7)

x(x² - 7x + 10) - 7(x² - 7x + 10)

x³ - 7x² + 10x - 7x² + 49x - 70

x³ - 7x² - 7x² + 10x + 49x - 70

x³ - 14x² + 59x - 70

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2 years ago
The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

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Answer:

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It’s to different from the other numbers

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