Part A:
# of shirts bought in total (T)times cost of each shirt (E) =X. X times .5 (same as 5%)= shipping charge (S) =
first: T*E=X. second: X*.5=S
Part B:
vendor 1:
# of shirts bought (A) times cost of each shirt (B) plus shipping charge(C) times 10%=T. A*B+C*.10=T
vendor 2:
# of shirts bought (A) times cost of each shirt (B) plus shipping charge (C) minus $20= T. A*B+C-20=T
Part C:
vendor 1:
15*16=240 (total # of shirts * cost of ea.)
240+8= 248 (1st answer + $8 of shipping)
248*.10= 24.80 (2nd answer * 10% discount)
248-24.80= [223.20] (2nd answer - 10%)
vendor 1 total cost: 223.20.
vendor 2:
15*18=270 (# of shirt bought * cost of ea.)
270+12.60=280.60 (answr 1 + shipping cost)
280.60-20=[260.60](answr 2 -$20discount)
vendor 2 total cost: 260.60.
$6.05 because 10.09 × 0.6 is 6.054, round down because the last number is less than 5, and you have 6.05.
Answer:
The probability that at most 3 attempts are required to produce a craft item with satisfactory quality is 0.9375
Step-by-step explanation:
Let E be a random variable denoting the event that an artist makes a craft item with satisfactory level.
Then the random variable E follows a Geometric distribution.
A Geometric distribution is defined as the number of failures (<em>k</em>) before the first success.
The probability function of Geometric distribution is:
, <em>p</em> = Probability of success and <em>k</em> = 0, 1, 2, 3...
The probability of success is, <em>p</em> = 0.5 and the number of failures is, <em>k</em> = 3.
Compute the probability of at most 3 attempts before the first success is:
![P(X\leq 3) =P(X=3)+P(X = 2)+P(X=1) +P(X = 0)\\=[(1-0.5)^{0}*0.5]+[(1-0.5)^{1}*0.5]+[(1-0.5)^{2}*0.5]+[(1-0.5)^{3}*0.5]\\=0.9375](https://tex.z-dn.net/?f=P%28X%5Cleq%203%29%20%3DP%28X%3D3%29%2BP%28X%20%3D%202%29%2BP%28X%3D1%29%20%2BP%28X%20%3D%200%29%5C%5C%3D%5B%281-0.5%29%5E%7B0%7D%2A0.5%5D%2B%5B%281-0.5%29%5E%7B1%7D%2A0.5%5D%2B%5B%281-0.5%29%5E%7B2%7D%2A0.5%5D%2B%5B%281-0.5%29%5E%7B3%7D%2A0.5%5D%5C%5C%3D0.9375)
Therefore, the probability that at most 3 attempts are required to produce a craft item with satisfactory quality is 0.9375.
The equation is:
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)

t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.