Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
Addends are any of the numbers added together in an equation.
The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations.
For ex:
2 - (8 + 3) here, the 8 and 3 have to be grouped together before doing the subtraction.
Any addition problem without parentheses can be used for one where the grouping doesn't matter
Answer:
see below
Step-by-step explanation:
12.5x − 10.2 = 3(2.5x + 4.2) - 6
Use the distributive property to distribute the 3
12.5x − 10.2 = 7.5x + 12.6 − 6
Combine like terms
12.5x − 10.2 = 7.5x + 6.6
Add 10.2 to each side of the equation by using the addition property of equality
12.5x = 7.5x + 16.8
Subtraction 7.5x from each side of the equation by using the subtraction property of equality
5x = 16.8
Divide by 5 on each side by using the division property of equality
x = 3.36
Answer:
Step-by-step explanation:
Since both triangles are similar, we know this because they have 2 angles in common, they both have the same third angle.
To find the third angle, we use the angle sum. The sum of angles in a triangle will always equal 180 degrees. We are given a right angle which is 90 degrees and another angle, which is 53 degrees. Knowing this:
90 + 53 + x = 180 (I have chosen to call the third angle x)
when rearranging this we get
180 - 90 - 53 = x
now we solve
x = 37 degrees
Hope this helps,
Cate
Answer:
Since the length of the drawing is 200 ft. and equivalent to 13.33 in. with a scale of 15 ft to 1 in. and the length of the paper is 11 in., Adoncia's drawing will not fit on the sheet of paper
Step-by-step explanation:
The given parameters are;
The scale of the drawing is 15 ft = 1 in.
The actual dimensions of the monument;
Height = 80 ft.
Length = 200 ft.
Therefore, we have;
The required dimension of the paper height = 80/15 = 16/3 = 5.33 in.
The required dimension of the paper length = 200/15 = 40/3 = 13.33 in.
The given paper dimension by 11 in. which is of a dimension of that of a standard letter paper size of 8.5 in. by 11 in.
Drawing length, 13.33 in. > Paper length > 11 in.
Adoncia's drawing will not fit on the sheet of paper.
