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Alenkasestr [34]

2 years ago

9

Once a week, Ms.Conrad selects one student at random from her class list to win a "no homework" pass. There are 17 girls and 18

boys in the class. rounded to the nearest percent, what is the probability that a girl will win a "no homework" pass two weeks in a row?

1 answer:

3241004551 [841]2 years ago

6 0

Well I will be 19×18= 342

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Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya had bought 2 burgers

Ber [7]

Let
x-------> the cost of the burger
y-------> the cost of the <span>sandwiches

we know that
3x+2y=27-----> equation 1
2x+y=27-11-----> 2x+y=16-----> multiply by -2-----> -4x-2y=-32--> equation 2

adds equation 1 and equation 2
</span> 3x+2y=27
-4x-2y=-32
<span>----------------
-x=27-32-----> x=5
3*5+2y=27----> 2y=27-15-----> y=6

therefore

the answer is the option
</span><span>3) The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6).</span>

3 0

2 years ago

A glass ball is packed in the box shown. Which expression represents the volume of foam padding needed to fill the space in the

zhuklara [117]

Answer: (27- 4/3 pi) r^3

Step-by-step explanation: 1. Volume of a cube: V= a^3, V= 3^3 , V=27

2. Volume of a sphere: V=4/3 pi r^3 ......

5 0

2 years ago

which expression finds the measure of an angle that is coterminal with a 126° angle? 126° (275n)°, for any integer n 126° (375n)

Vilka [71]

(720n) for any integer

3 0

2 years ago

Read 2 more answers

Tanisha and Neal are simplifying the expression . They each began the same way. Tanisha’s Work Neal’s Work Which statements are

valentina_108 [34]

Answer:

The correct simplified answer is $\frac{1}{8} \left (\frac{x}{ y} \right )^{8}$ or $\frac{x^8}{81\cdot y^8}$

Step-by-step explanation:

Here we have the expression as

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4}$

Tanisha's work

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4} = \left (\frac{(x^2)(y^{-2})}{3} \right )^{4}$

Neal's work is

$\left (\frac{(x^4)(y^{-5})}{3(x^2)(y^{-3})} \right )^{4} = \left (\frac{(x^{16})(y^{-20})}{3^4(x^8)(y^{-12})} \right )$

The correct simplified answer is $\frac{x^8}{81\cdot y^8}$ .

which can also be expressed as

$\frac{1}{8} \left (\frac{x}{ y} \right )^{8}$

Both form represent simplified forms of the original equation.

8 0

2 years ago

Read 2 more answers

Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche

aliya0001 [1]

Answer:

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

Step-by-step explanation:

Rate of water pouring out in the cone = R= $\frac{3}{2} inch^3/s$

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

$\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}$

r = h/2

Volume of the cone = $V=\frac{1}{3}\pi r^2h$

$V=\frac{1}{3}\pi r^2h$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}$

$\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}$

$\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

h = 4 inches

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2$

$\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s$

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

6 0

2 years ago