Answer:
D
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y )
That is the x- coordinate remains unchanged while the y- coordinate is the negative of the original y- coordinate.
Given
A(- 3, 5 ) → A'(- 3, - 5 )
B(2, 8 ) → B'(2, - 8)
C(- 4, - 5 ) → C'(- 4, 5 )
The rule for reflection in the x- axis has been applied here → D
Answer: Paul should receive $2.25 as a change from the cashier.
Step-by-step explanation: If Paul gave the cashier 1 fifty dollar bill, 4 twenty dollar bills, and 7 five dollar bills, that would add up to $165.
50+4*20+7*5=165
165-162.75=2.25
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Answer:
15x+13y> 3,000
Step-by-step explanation:
We know that the floor ticket cost 15$ and the balcony cost 12$ so we put that in an inequality with their given variables. We also know they want to make more than 3,000 so it is a greater than symbol.
5. 23, 30, 38
7. slope intercept form will be like a fraction so if your point is (4,5) graph it go down -2 and over -2 to get your answer
We can start solving this problem by first identifying what the elements of the sets really are.
R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.
Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).
W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.
W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.
R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.
0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.
∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).
{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be equal to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).
-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.