Answer:
10.99%.
Step-by-step explanation:
We have been given that the Smiths bought new furniture that cost $3,298.00. The store offered them an option of putting $600 down and making equal payments of $300 a month for 10 months.
First of all, we will find amount paid by down-payments in 10 months.

Total amount paid by Smiths:
.
Now we will find amount paid in interest by subtracting initial amount from total amount.

10 months = 10/12 year =5/6 year.
Now, we will use simple interest formula to solve for interest rate.




Therefore, the annual interest rate is 10.99%.
Answer:
The minimum value of the bill that is greater than 95% of the bills is $37.87.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What are the minimum value of the bill that is greater than 95% of the bills?
This is the 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.




The minimum value of the bill that is greater than 95% of the bills is $37.87.
Answer:
26 days
Step-by-step explanation:
If 6 days = rs. 2130
then 1 day = (2130 × 1) ÷ 6
Therefore 1 day = rs 355
For rs. 9230, the number of days he worked:
= 9230 ÷ 355
= 26 days
"Then I will need an average quality score of <u>3.28</u> to meet 85.28 goal."
<u>Step-by-step explanation</u>:
- current average quality score = 82
- improvement on average quality score = 4% of 82
⇒ (4/100)
82
⇒ 82/25
⇒ 3.28
The improved average quality score = 82+3.28 = 85.28
The employee needs an average quality score of 3.28 to meet the goal of 85.28