Answer:
The length side of the pre-image is 16 units
Step-by-step explanation:
we know that
The length side of the image is equal to the length side of the pre-image multiplied by the scale factor
or
The length side of the pre-image is equal to the length side of the image divided by the scale factor
in this problem we have that
The scale factor is 1/2
The length side of the image is 8 units
therefore
8/(1/2)=16 units
The length side of the pre-image is 16 units
When putting data into a class for this case, 0.350 - 0.359, they should be within the class boundaries. The class boundaries are 0.3495 and 0.3595. So, the data that will go into that class are 0.356 and 0.358. The record 0.349 is not included since it is below 0.3495. Therefore, there are only two values in the class.
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Approximately 1718 have a score within that range.
We calculate the z-score for each end of this spectrum:
z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.
For the upper end:
z = (3.7-3.1)/0.3 = 0.6/0.3 = 2
Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.
The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.
This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
Answer:
Step-by-step explanation:
275 (slushy) in a cup.
After 13 seconds, 210 milliliters of slushy remained.
divide the original by the seconds then the answer by the left over. And then you get your answer.
hope it helps!
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