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olga55 [171]
2 years ago
8

Two fifths of the square of the number j in algebraic exprission

Mathematics
2 answers:
meriva2 years ago
8 0

Answer: \dfrac{2}{5}j^2

Step-by-step explanation:

The given mathematical statement : "two fifths of the square of the number j "

To write the algebraic expression for the given mathematical statement.

We can write  square of the number j as j^2

and two-fifth as \dfrac{2}{5}

Then, the final algebraic expression will be :-

\dfrac{2}{5}j^2

Tomtit [17]2 years ago
5 0
Two-fifths (\frac{2}{5}) of the square of the number j (j²)

 \frac{2}{5}j²
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If pq=9 and qr=28, find PR
Ksenya-84 [330]
PQ = 9
QR = 28

Note, there is a Q in each line

Combine the two lines: PQ + QR = PR

plug in the numbers to corresponding variables

9 + 28 = PR

PR = 37

hope this helps
8 0
2 years ago
The endpoints of line AB are A(2, 2) and B(3, 8). Line AB is dilated by a scale factor of 3.5 with the origin as the center of d
Musya8 [376]
A` ( 7, 7 )
B ` ( 10.5, 28 )
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d ( A` B `) = √ ( 10.5 - 7 )² + ( 28 - 7 )² = √ 3.5² + 21² = 
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Answer: 
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7 0
2 years ago
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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
1 year ago
Find the surface area of the regular pyramid shown in the accompanying diagram. If necessary, express your answer in simplest ra
Oksana_A [137]

Answer:

The area of the pyramid is 360 unit²

Step-by-step explanation:

Given

Base Edge, a = 10

Height, h = 12

Required

Determine the surface area

The surface area of a regular pyramid is calculated as thus;

A = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}

Substitute values for a and h

A = 10^2 + 2 * 10 * \sqrt{\frac{10^2}{4} + 12^2}

Evaluate all squares

A = 100 + 2 * 10 * \sqrt{\frac{100}{4} + 144}

A = 100 + 2 * 10 * \sqrt{25 + 144}

A = 100 + 2 * 10 * \sqrt{169}

Take positive square root of 169

A = 100 + 2 * 10 * 13

A = 100 + 260

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<em>Hence, the area of the pyramid is 360 unit²</em>

4 0
1 year ago
The grade point average (GPA) of the students at Lakeview High School is normally distributed with a mean of 3.1 and a standard
Morgarella [4.7K]
Approximately 1718 have a score within that range.

We calculate the z-score for each end of this spectrum:

z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.

For the upper end:
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Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.

The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.

This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
4 0
1 year ago
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