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2 years ago

What is 1\3 (12 - 9y)

Mathematics

2 answers:

steposvetlana [31]2 years ago

5 0

4-3y I took this quiz :)

iren [92.7K]2 years ago

3 0

Answer:

4-3y

Hope this helps!

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(1 point) If f(t) is continuous for t≥0, the {\it Laplace transform} of f is the function F defined by F(s)=∫[infinity]0f(t)e−st

QveST [7]

Answer:

The Laplace transform of f(t) = 1 is given by

F(s) = (1/s) for all s>0

Step-by-step explanation:

Laplace transform of a function f(t) is given as

F(s) = ∫∞₀ f(t) e⁻ˢᵗ dt

Find the Laplace transform for when f(t) = 1

F(s) = ∫∞₀ 1.e⁻ˢᵗ dt

F(s) = ∫∞₀ e⁻ˢᵗ dt = (1/s) [-e⁻ˢᵗ]∞₀

= -(1/s) [1/eˢᵗ]∞₀

Note that e^(∞) = ∞

F(s) = -(1/s) [(1/∞) - (1/e⁰)]

Note that (1/∞) = 0

F(s) = -(1/s) [0 - 1] = -(1/s) (-1) = (1/s)

Hope this Helps!!!

8 0

2 years ago

Which of the following demonstrates the commutative property across multiplication for 2 × 10 × 7 A. 2 + 10 × 7 B. 2 ×

Yuliya22 [10]

The correct answer is C. 10×7×2

3 0

2 years ago

Read 2 more answers

The number of messages that arrive at a Web site is a Poisson distributed random variable with a mean of 6 messages per hour. Ro

QveST [7]

Answer:

a) There is a 16.0623% probability that 5 messages are received in 1 hour.

b) There is a 11.5880% probability that 10 messages are received in 1.5 hours.

c) There is a 22.4042% probability that 2 messages are received in 0.5 hours.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have a mean of 6 messages per hour.

(a) What is the probability that 5 messages are received in 1 hour?

Find the value of P when $x = 5$ and $\mu = 6$

$P(X = 5) = \frac{e^{-6}*(6)^{5}}{(5)!} = 0.160623$

There is a 16.0623% probability that 5 messages are received in 1 hour.

(b) What is the probability that 10 messages are received in 1.5 hours?

The mean is 6 messages in one hour.

For 1.5 hours, the mean is 6*1.5 = 9 messages.

We have to find the value of P when $x = 10$ and $\mu = 9$ .

$P(X = 10) = \frac{e^{-9}*(9)^{10}}{(10)!} = 0.115880$

There is a 11.5880% probability that 10 messages are received in 1.5 hours.

(c) What is the probability that less than 2 messages are received in 1/2 hour?

The mean is 6 messages in one hour.

For 0.5 hours, the mean is 6*0.5 = 3 messages.

We have to find the value of P when $x = 2$ and $\mu = 3$ .

$P(X = 10) = \frac{e^{-3}*(3)^{2}}{(2)!} = 0.224042$

There is a 22.4042% probability that 2 messages are received in 0.5 hours.

6 0

2 years ago

an original piece of art work is 3 feet by 2.5 feet. a reprint of the artwork is 6 inches by 5 inches. are the pieces similar? i

RoseWind [281]

For this case we observe that the dimensions of the original piece are:
3 feet
2.5 feet
Let's multiply these dimensions by a scale factor k:
3 * k
2.5 * k
We match the new dimensions with their respective values:
3 * k = 6
2.5 * k = 5
Clearing k we have:
k = 6/3 = 2
k = 5 / 2.5 = 2
Since the value of k is the same, then the pieces are similar.
Answer:
The pieces are similar.
The ratio of their corresponding side lengths is:
k = 2

3 0

2 years ago

A cyclist rides at an average speed of 31 miles per hour. The cyclist’s speed, s, can differ from the average by as much as 8 mi

Shalnov [3]

In this compound inequality X should be 8.

4 0

2 years ago

Read 2 more answers