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Alex Ar [27]
2 years ago
11

One week, Claire earned $272.00 at her job when she worked for 17 hours. If she is paid the same hourly wage, how many hours wou

ld she have to work the next week to earn $448.00?
Mathematics
2 answers:
lbvjy [14]2 years ago
6 0

Answer:

34 represents how many hours she worked. and 544 represents how much she got paid.

Step-by-step explanation:

since you know that every 17 hours she gets paid $272 you would do 272 times 2 which is 544. then do 17 times 2 which is 34. 34 represents how many hours she worked. and 544 represents how much she got paid.

DochEvi [55]2 years ago
4 0

Answer: 448 hours

Step-by-step explanation:

272 divided by 17 = hourly wage

hourly wage= 16$

448 divided by 16 = 28 weeks

28 x 16= 448 hours

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Three couples and two single individuals have been invited to an investment seminar and have agreed to attend. Suppose the proba
Maksim231197 [3]

Answer:

(a) Probability mass function

P(X=0) = 0.0602

P(X=1) = 0.0908

P(X=2) = 0.1704

P(X=3) = 0.2055

P(X=4) = 0.1285

P(X=5) = 0.1550

P(X=6) = 0.1427

P(X=7) = 0.0390

P(X=8) = 0.0147

NOTE: the sum of the probabilities gives 1.0068 for rounding errors. It can be divided by 1.0068 to get the adjusted values.

(b) Cumulative distribution function of X

F(X=0) = 0.0602

F(X=1) = 0.1510

F(X=2) = 0.3214

F(X=3) = 0.5269

F(X=4) = 0.6554

F(X=5) = 0.8104

F(X=6) = 0.9531

F(X=7) = 0.9921

F(X=8) = 1.0068

Step-by-step explanation:

Let X be the number of people who arrive late to the seminar, we can assess that X can take values from 0 (everybody on time) to 8 (everybody late).

<u>For X=0</u>

This happens when every couple and the singles are on time (ot).

P(X=0)=P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot)\\\\P(X=0)=(1-0.43)^{5}=0.57^5= 0.0602

<u>For X=1</u>

This happens when only one single arrives late. It can be #4 or #5. As the probabilities are the same (P(#4=late)=P(#5=late)), we can multiply by 2 the former probability:

P(X=1) = P(\#4=late)+P(\#5=late)=2*P(\#4=late)\\\\P(X=1) = 2*P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=late)*P(\#5=ot)\\\\P(X=1) = 2*0.57*0.57*0.57*0.43*0.57\\\\P(X=1) = 2*0.57^4*0.43=2*0.0454=0.0908

<u>For X=2</u>

This happens when

1) Only one of the three couples is late, and the others cooples and singles are on time.

2) When both singles are late , and the couples are on time.

P(X=2)=3*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=2)=3*(0.43*0.57^4)+(0.43^2*0.57^3)=0.1362+0.0342=0.1704

<u>For X=3</u>

This happens when

1) Only one couple (3 posibilities) and one single are late (2 posibilities). This means there are 3*2=6 combinations of this.

P(X=3)=6*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=3)=6*(0.43^2*0.57^3)=6*0.342=0.2055

<u>For X=4</u>

This happens when

1) Only two couples are late. There are 3 combinations of these.

2) Only one couple and both singles are late. Only one combination of these situation.

P(X=4)=3*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=4)=3*(0.43^2*0.57^3)+(0.43^3*0.57^2)\\\\P(X=4)=3*0.0342+ 0.0258=0.1027+0.0258=0.1285

<u>For X=5</u>

This happens when

1) Only two couples (3 combinations) and one single are late (2 combinations). There are 6 combinations.

P(X=6)=6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=6*(0.43^3*0.57^2)=6*0.0258=0.1550

<u>For X=6</u>

This happens when

1) Only the three couples are late (1 combination)

2) Only two couples (3 combinations) and one single (2 combinations) are late

P(X=6)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=ot)*P(\#5=ot)+6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=(0.43^3*0.57^2)+6*(0.43^4*0.57)\\\\P(X=6)=0.0258+6*0.0195=0.0258+0.1169=0.1427

<u>For X=7</u>

This happens when

1) Only one of the singles is on time (2 combinations)

P(X=7)=2*P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=ot)\\\\P(X=7)=2*0.43^4*0.57=0.0390

<u>For X=8</u>

This happens when everybody is late

P(X=8)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=l)\\\\P(X=8) = 0.43^5=0.0147

8 0
1 year ago
Convert 5 3/4 to a decimal round to the nearest tenth​
matrenka [14]

Answer: 5.75

Step-by-step explanation:

3/4=.75 then add the 5

6 0
2 years ago
Read 2 more answers
y = x2 + 11x + 24 is equivalent to the graph of which equation? y = (x + 8)(x + 3) y = (x + 4)(x + 6) y = (x + 9)(x + 2) y = (x
Montano1993 [528]

Answer:

First option: y=(x + 8)(x + 3)

Step-by-step explanation:

Given the quadratic equation y = x^2 + 11x + 24, you need to factor it.

To do this, you need to find two number that when you add them you get 11 and when you multply them you get 24. These numbers are: 8 and 3.

Therefore, knowing this, you can factor the quadratic equation:

y = x^2 + 11x + 24\\\\y=(x + 8)(x + 3)

Then, y = x^2 + 11x + 24 is equivalent to the graph of the equation y=(x + 8)(x + 3), which matches with the first option.

7 0
2 years ago
A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio
steposvetlana [31]

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean \mu = 105 and a standard deviation \sigma = 7. For a value x we compute the z-score as (x-\mu)/\sigma, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

4 0
2 years ago
Read 2 more answers
Use Pythagorean identities to prove whether ΔLMN is a right, acute, or obtuse triangle. Show all work for full credit.
liq [111]
Using Pythagorean identities:
 
If the sum of the height and base squared is greater than the hypotenuse squared, it would be an acute triangle.

If the sum of the height and base squared is less than the hypotenuse squared, it would be an obtuse triangle.

If the sum of the height and base squared is equal to the hypotenuse squared, it would be a right triangle.

The height = 10
The base = 24

10^2 + 24^2 = 100 + 576 = 676

The hypotenuse = 27 = 27^2 = 729

Because the sum of the height and base squared (676) is smaller than the hypotenuse squared (729) the triangle  is an obtuse triangle.


5 0
2 years ago
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