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Ahat [919]
1 year ago
9

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Mathematics
2 answers:
Debora [2.8K]1 year ago
6 0

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

Scorpion4ik [409]1 year ago
5 0

Answer:

is one way to determine the factors of  by grouping

Solution:

Factoring by grouping means that you will group terms with common factors before factoring

Given expression is:

Group the first two terms together and then the last two terms together.

We can see that  is common in first two terms

And 3 is common in last two terms

Factor them out

Step-by-step explanation:

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Answer: 300ft

Step-by-step explanation:

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The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
oksian1 [2.3K]
<span>Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.

</span>y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 <span>it is true
proof
</span><span>for x=0  and y=10,  y ≤ 40 – x equivalent to 10<40-0=40 it is true
</span>x=10, y=30,   <span>y ≤ 40 – x  equivalent to 30=40-10=30 it is true

the answer is </span><span>A) Yes, Chaneece found the correct solution. </span>
5 0
1 year ago
Read 2 more answers
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

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Answer:

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Step-by-step explanation:

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"An adult Welsh Corgi is always going to be shorter than an adult Basset Hound."

"Basset hounds tend to be a little over two inches taller than Welsh Corgis, but have a higher variability in height.

whichever just not the other ones good luck!

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Write an arithmetic series for which S5 = 10.
Ludmilka [50]
S5=10 means the 5th number is 10. 
So the arithmetic sequence is s1, s2,s3, s4, 10
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