Answer:
3l= c
Step-by-step explanation:
as use 3 cup of cranberry juice, lemonade will be used 1 cup.
Answer:
C
Step-by-step explanation:
Consumed = 1500
Burned = 400
Calorie Count total = 1500 - 400 = 1100
His target is 1900, so he will need 1900 - 1100 = 800 calories to consume more
So, 1100 is NOT a viable solution because he will go over 1900 if that happens. Hence, C is the correct choice.
Answer:
just copy and paste below
Step-by-step explanation:
Step-by-step explanation:Sample Response: The equation could model a scenario determining the number of players on each team in a league of five teams, if 2 players have to be taken out of the possible players to be referees and to keep score. There will be 11 players on each team.
Let's start first by writing down the given:
σ = 100
sample mean = 450
sample size = 25
These information, plus the fact that we know that the population is approximately normally distributed, would tell us that we can use the
normal distribution curve in analyzing the problem.
A confidence interval of the mean is just a range statistically estimated to contain the population mean. For a 90% confidence interval, we would look at the Z-table and see where 90% of the data falls. We'll notice that it will fall within
1.645 standard deviations of the mean.
Next, we look for the standard error of the mean. This will have a formula

The standard error would just therefore be equal to

Lastly, we just get the product of the standard error and 1.645 and add it to 450 for the maximum value and subtract it to 450 for the minimum value.

ANSWER: 417.1<μ<482.9
Answer:
a) The expected number of questions that are answered correctly by both A and B = 11 (7 + 4).
b) The Variance of the number of questions that are answered correctly by either A or B = 2.25.
Step-by-step explanation:
Number of questions in the examination = 10
Probability of A's answer being correct = 0.7
Probability of B's answer being correct = 0.4
The expected number of questions that are answered correctly by both A and B:
Probability of Expected
Correct Answer Value Variance
A 0.7 7 (0.7 * 10) 2.25
B 0.4 4 (0.4 * 10) 2.25
Total expected value = 11
Mean = 5.5 2.25