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2 years ago

Elsa tries to solve the following equation, and determines there is no solution. Is she correct? Explain.

Mathematics

2 answers:

GaryK [48]2 years ago

7 0

The spot on correct answer for this is....

Identify the system of equations that can be graphed to solve the problem.

Use the change of base formula.

Determine that the graphs of the two equations do not intersect.

Determine that Elsa is correct; the equation has no solution.

Vlad [161]2 years ago

3 0

Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4. Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667.

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Step-by-step explanation:

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The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in

Marina86 [1]

Answer:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

$\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3$

We can express this formula like this:

$\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

$\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2$

If we operate and we take out the 1/4 as a factor we got this:

$\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}$

We can cancel $n^2$ and we got

$\lim_{n\to\infty} \frac{(n+1)^2}{n^2}$

We can reorder the terms like this:

$\lim_{n\to\infty} (\frac{n+1}{n})^2$

We can do some algebra and we got:

$\lim_{n\to\infty} (1+\frac{1}{n})^2$

We can solve the square and we got:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})$

And when we apply the limit we got that:

$\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1$

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2 years ago

HELP PLEASE. A pizza shop charges customers based on the area of the pizza they order. The cost of a pizza in dollars can be rep

san4es73 [151]

For this case we have that the cost of each pizza is given by the following function:

$S (r) = 0.1 \pi * r ^ 2$

Where:

r: It's the radius of the pizza

IF a pizza cost $26.32 we have:

$26.32 = 0.1 \pi * r ^ 2$

We cleared the radius, using $\pi = 3.14$ :

$\frac {26.32} {0.1} = \pi * r ^ 2\\263.2 = 3.14r ^ 2\\\frac {263.2} {3.14} = r ^ 2\\83.82 = r ^ 2\\r = \pm \sqrt {83.82}$

We choose the positive value:

$r = 9.15$

So, the radius of the pizza is $9.16 \ in$

Then, the diameter is: $2r = 2 * 9.15 = 18.30 \ in$

Finally, the diameter of the pizza is: $18.30 \ in$

Answer:

Option B

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Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

Consider the provided information.

Let us consider he walks x miles at the rate of 4 miles per hour.

As we know $Time=\frac{Distance}{Speed}$

Therefore, time taken is: $Time=\frac{x}{4}$

He get a taxi for (31-x) miles at the rate of 50 miles per hour.

Therefore, time taken is: $Time=\frac{31-x}{50}$

It took 2 hours after he started.

That means the sum of time take is 2 hours.

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Hence he walk 6 miles and he get a taxi for 31-6=25 miles.

He pays to the cab driver for 25 miles.

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