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zaharov [31]
2 years ago
10

What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?

Mathematics
2 answers:
soldi70 [24.7K]2 years ago
8 0

Answer:

Its A

Step-by-step explanation:

I just took the test

OWO

Hatshy [7]2 years ago
5 0

The root sof this quadratic equation are -4 and 2.5.


The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.


\frac{-b +/- \sqrt{b^{2}- 4ac}}{2a}


In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.


\frac{3 +/- \sqrt{-3^{2}- 4(-2)(20)}}{2(-2)}

\frac{3 +/- \sqrt{9 + 160}}{-4}

\frac{3 +/- 13}}{4}


Now you separate and get the two separate answers. First the positive.


\frac{3 + 13}}{4}

\frac{16}}{4}

4


Now the negative


\frac{3 - 13}}{4}

\frac{-10}}{4}

-2.5

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5 people.

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1 year ago
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To find the area of the sector, you would multiply the area by the ratio of the the sector angle over 360.
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7 0
2 years ago
What is the constant of variation, k, of the direct variation, y = kx, through (5, 8)? k = – k equals negative StartFraction 8 O
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The value of constant of variation "k" is k = \frac{8}{5} \text{ or } 1.6

<em><u>Solution:</u></em>

Given that the direct variation is:

y = kx ----- eqn 1

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<em><u>To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1</u></em>

8 = k \times 5\\\\k = \frac{8}{5}\\\\k = 1.6

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A piece of ribbon is cut into two shorter pieces in the ratio 2.8:1.25. The divfference in the length of the two shorter pieces
MariettaO [177]

Answer:

210.6 cm

Step-by-step explanation:

Given that a piece of ribbon is cut into two shorter pieces in the ratio 2.8:1.25.

So that means length of the first smaller piece = 2.8x

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6 0
1 year ago
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Strike441 [17]

Answer:

Step-by-step explanation:

Find the quotient.

(4.86 × 109)

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6

What is the coefficient in the quotient?

2  

Which operation produced the exponent of the power in the quotient?

Subtracting the original exponents

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