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Maslowich
1 year ago
12

We are told that the two players, taken together, scored a total of 49 points. What is the probability that player A scored firs

t?
Mathematics
1 answer:
mario62 [17]1 year ago
7 0

Answer:

1/2 or 50% probability

Step-by-step explanation:

There are just two players, player A and player B. Since it is between this two players, for player A to score first we would have:

AB where player A is the first player to score, we wouldn't have BA since player would not be the first here

Probability = number of favorable outcomes/total number of outcomes

Therefore probability of A being the first player = number of A/total number of players

=1/2 = 0.50

There is therefore a 50% chance of A being the first player

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Step-by-step explanation: MARK ME BRAINLIEST!!!!

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11. The probability that a dessert sold at a certain cafe contains chocolate is 75%. The probability that a dessert containing c
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What dose 0.07x1.22 eaqual
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0.07 * 1.22

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2 years ago
Read 2 more answers
Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

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2 years ago
Which best describes the graph of the cubic function f(x) = x3 + x2 + x + 1?
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Answer:

Option A

Step-by-step explanation:

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<em>See attached graph for reference</em>

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2 years ago
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