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asambeis [7]
1 year ago
6

The table represents an exponential function.

Mathematics
2 answers:
Minchanka [31]1 year ago
8 0

we know that

The multiplicative rate of change of the exponential function between two points is equal to

[f(b) / f(a) ] / (b-a)

Let

A(1,6)\\B(2,4)

we have that

f(a)=6\\f(b)=4\\a=1\\b=2

substitute in the formula

[4 / 6 ] / (2-1)=4/6=2/3

Let

A(3,8/3)\\B(4,16/9)

we have that

f(a)=8/3\\f(b)=16/9\\a=3\\b=4

substitute in the formula

[(16/9) / (8/3) ] / (4-3)=48/72=2/3

therefore

<u>the answer is the option</u>

B.) 2/3



stepladder [879]1 year ago
8 0
The best and most correct answer among the choices provided by the question is the second choice. T<span>he multiplicative rate of change of the function is 2/3. I </span>hope my answer has come to your help. God bless and have a nice day ahead!
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To answer the question above, we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,
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13 (c)

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Solve the equation. Negative StartFraction 9 Over 15 EndFraction y + StartFraction 3 Over 21 EndFraction = StartFraction 5 Over
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Answer:

Step-by-step explanation:

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The extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia. One of the chemical compounds prod
True [87]

Answer:

a) 57.35%

b) 99.99%

c) 68.27%

Step-by-step explanation:

When we have a random variable X that is normally distributed with mean \large\bf \mu and standard deviation \large\bf \sigma, then  

The probability that the random variable has a value less than a, P(X < a) = P(X ≤ a) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the left of a.

The probability that the random variable has a value greater than b, P(X > b) = P(X ≥ b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the right of b.

The probability that the random variable has a value between a and b, P(a < X < b) = P(a ≤ X ≤  b) = P(a < X ≤  b)= P(a ≤ X < b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma between a and b.

In this case, the random variable is the collagen amount found in the extract of the plant. The mean is 63 g/ml and the standard deviation is 5.4 g/ml

(a) What is the probability that the amount of collagen is greater than 62 grams per mililiter?

As we have seen, we need to find the area under the normal curve with mean 63 and standard deviation 5.4 to the right of 62 (see picture).

You can find this value easily with a calculator or a spreadsheet. If you prefer the old-style, then you have to standardize the values and look up in a table.

<em>If you have access to Excel or OpenOffice Calc, you can find this value by introducing the formula: </em>

<em>1- NORMDIST(62,63,5.4,1) in Excel </em>

<em>1 - NORMDIST(62;63;5.4;1) in OpenOffice Calc </em>

<em>and we will get a value of 0.5735 or 57.35% </em>

(b) What is the probability that the amount of collagen is less than 90 grams per mililiter?

Now we want the area to the left of 90

<em>NORMDIST(90,63,5.4,1) in Excel </em>

<em>NORMDIST(90;63;5.4;1) in OpenOffice Calc </em>

You will get a value of 0.9999 or 99.99%

(c) What percentage of compounds formed from the extract of this plant fall within 1 standard deviations of the mean?

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<em>In Excel </em>

<em>NORMDIST(68.4,63,5.4,1) - NORMDIST(57.6,63,5.4,1)  </em>

<em>In OpenOffice Calc  </em>

<em>NORMDIST(68.4;63;5.4;1) - NORMDIST(57.6;63;5.4;1)  </em>

In any case we get a value of 0.6827 or 68.27%

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Mia’s work to find the slope of a trend line through the points (3, 10) and (35, 91) is shown below.
pochemuha
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 C: Mia switched the numerator and the denominator.
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1 year ago
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