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zhannawk [14.2K]
2 years ago
10

Triangle HAM is reflected over the y-axis using the rule (x, y) → (−x, y) to create triangle H′A′M′. If a line segment is drawn

from point A to point A′, which statement would best describe the line segment drawn in relation to the y-axis?

Mathematics
2 answers:
Rufina [12.5K]2 years ago
6 0

Answer:

The segment drawn and the y-axis are congruent to each other.

vladimir1956 [14]2 years ago
4 0

Answer:

the last one

i think it right

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The data below shows the heights in inches of 10 students in a class. StudentHeight, in inches Student 153 Student 252.5 Student
Marianna [84]

Question not correct, so i have attached the correct question.

Answer:

SE = 0.59

Step-by-step explanation:

The mean of the students height is;

x' = (53 + 52.5 + 54 + 51 + 50.5 + 49.5 + 48 + 53 + 52 + 50)/10

x' = 51.35

Now, deviation from the mean for each height;

53 - 51.35 = 1.65

52.5 - 51.35 = 1.15

54 - 51.35 = 2.65

51 - 51.35 = -0.35

50.5 - 51.35 = -0.85

49.5 - 51.35 = -1.85

48 - 51.35 = -3.35

53 - 51.35 = 1.65

52 - 51.35 = 0.65

50 - 51.35 = -1.35

Now, square of the deviations above;

1.65² = 2.7225

1.15² = 1.3225

2.65² = 7.0225

-0.35² = 0.1225

-0.85² = 0.7225

-1.85² = 3.4225

-3.35² = 11.2225

1.65² = 2.7225

0.65² = 0.4225

-1.35² = 1.8225

Sum of the squared deviations;

2.7225 + 1.3225 + 7.0225 + 0.1225 + 0.7225 + 3.4225 + 11.2225 + 2.7225 + 0.4225 + 1.8225 = 31.525

Let's divide the sum by the DF of n - 1 i.e 10 - 1 = 9.

Thus;

31.525/9 = 3.50278

Taking the square root of that gives us the standard deviation.

Thus;

s = √3.50278

s = 1.8716

Formula for standard error is;

SE = s/√n

SE = 1.8716/√10

SE = 0.59

8 0
2 years ago
In a standard game of pool, there are 15 balls labeled 1 through 15. a) In how many ways can the 15 balls be ordered? (5 points)
katovenus [111]

Answer:

<h2>a) 1.308*10¹² ways</h2><h2>b) 455 way</h2>

Step-by-step explanation:

If  there are 15 balls labeled 1 through 15 in a standard football game, the order of arrangement of the 15 balls can be done in 15! ways.

15! = 15*14*13*12*11*10*9*8*7*6*5*4*3*2

15! = 1.308*10¹² ways

b)  If 3 of the 15 balls are to be chosen if order does not matter, this can be done in 15C3 number of ways. Since we are selecting some balls out of the total number of balls, we will use the concept of combination.

Using the combination formula nCr = n!/(n-r)!r!

15C3 = 15!/(15-3)!3!

15C3 = 15!/12!3!

15C3 = 15*14*13*12!/12!*6

15C3 = 15*14*13/6

15C3 = 455 ways

7 0
2 years ago
During the early 20th century, in what way was the radio better than the phonograph in encouraging the concept of crosspollinati
ololo11 [35]

C. Phonograph were inferior in sound quality.

Step-by-step explanation:

Researches have shown that plants respond to the sounds of their pollinator.

Some plants begin to produce a greater amount of nectar and some begin to vibrate to attract the attention of the pollinators towards them.

Greater the intensity of the sound of the pollinator, the faster the reaction will be.

Phonographs have a sound of lower intensity when compared to the intensity of sound produced by the radio.

Thus the radio was better than the phonograph in encouraging the concept of cross-pollination.

6 0
2 years ago
PICK MORE THAN ONE ANSWER:
ss7ja [257]

Answer:

The correct answers are "After adding the 0 test score, the mean would be affected.", ad "Before the missed test, Eva’s median score was 91".

Step-by-step explanation:

We know that the mean and median scores would not be helpful in determining Eva's abilities since the 0 is not a representation of how much she knows. However, it will affect the average as adding a 0 to the numerator and a 1 to the denominator will lower the average.

Finally, we can tell the median is 91 before added as when we line up the scores in ascending order, the middle number is 91.

82, 90, 91, 96, 100

4 0
2 years ago
Read 2 more answers
The random variable X, representing the number of cherries in a cherry puff, has the following probability distribution:x: 4 - 5
marta [7]

Answer:

Step-by-step explanation:

Given is the probability distribution of a random variable X

X 4 5 6 7 Total

P 0.2 0.4 0.3 0.1 1

x*p 0.8 2 1.8 0.7 5.3

x^2*p 3.2 10 10.8 4.9 28.9

a) E(X) = Mean of X = sum of xp = 5.3

Var(x) = 28.9-5.3^2=0.81

Std dev = square root of variance = 0.9

------------------------------------

b) For sample mean we have

Mean = 5.3

Variance = var(x)/n = \frac{0.81}{{36} } \\=0.0225

c) P(\bar X

3 0
2 years ago
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